[SOLVED] PHP / JAVA echo out java help

[thisisnuts123]

hello guys

i have read some articles and am trying to figure out how to echo out java script.. i never really understand the consept..

any one can explain better?

 

phpfuntion()
{
$query  = "SELECT `itemnum` , `sitedat` FROM layout WHERE `set` = 'dropbox' ";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
        $site[0] = $row[1];
      } 	 	

 

i wana alert out site[0]

how can this be done thanks

[rajivgonsalves]

here you go

 

funtion()
{
$query  = "SELECT `itemnum` , `sitedat` FROM layout WHERE `set` = 'dropbox' ";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
        $site[0] = $row[1];

echo "<script>alert('{$site[0]}');</script>";
      } 		

 

[thisisnuts123]

thank u sir

[thisisnuts123]

ok i tried it and it is not working..

it will not send out an alert.

is this becuase it's inside a php funtion??

any way to assign it to a java variable and then send an alert out side of php funtion?

[rajivgonsalves]

well it depends where you are calling the function more code would be helpful as to where you are calling the function on the page

[thisisnuts123]

function update_dropbox($data_array, $col_check)
{
      	$i = 0;
$o = array();
foreach($data_array AS $set => $items)
{
foreach($items AS $item)
{
$item = mysql_escape_string($item);
       	$set  = mysql_escape_string($set);
$o[$i] = $items[$i];

       $query  = "SELECT `sitedat` FROM layout WHERE `item` = '$o[0]'";
       $result = mysql_query($query);
       $row = mysql_fetch_row($result);
       $sitevalue = $row[0];
       $i ++;
       
  	}
}
        echo "<script>alert('{$sitevalue}');</script>";

return $sitevalue;
}

 

function sajax_update($data)
{
  $data = parse_data($data);
  $website = update_dropbox($data, "AND (`set` = 'dropbox')");
  return $website;
  return 'y';
}

 

 

[thisisnuts123]

and this is the java funtion

 

function onDrop() {
          var data = DragDrop.serData('g1');
         x_sajax_update(data, confirm);
     

     }

[thisisnuts123]

so when an item is dropeed in to a drop box

 

drop box funtion is called and then it send info to sajax_update which then sends info to update funtion then i waan return the value back to java

[trq]

Firstly, you must understand that Java is not Javascript. Secondly, PHP is a server side language which is run on the server and then sends its response to the client. Javascript on the other hand is run on the client. You cannot simply call a Javascript function from PHP and vice versa.

[thisisnuts123]

it is using sajax so the information is passed properly to php

 

if i use a debuger program i can see

echo "<script>alert('{$site[0]}');</script>";

 

the variable getting populated.

 

but i can't figure out how to use sajax to now pass the information back to java

 

 

[trq]

but i can't figure out how to use sajax to now pass the information back to java

 

Um... as I just stated. That would be Javascript NOT Java. They are two completely different and unrelated beasts.

[thisisnuts123]

sorry i ment javascript

[thisisnuts123]

so.. any one?

[thisisnuts123]

just had another look at ajax and i was able to figure it out!!!

finaly !!!