[SOLVED] Login not working

farkewie · November 6, 2007

Cool,

If everything is working please topic solved.

Ads · November 6, 2007

but it is not working, It is saying i can;t view the page even when i enter in the Right info.

farkewie · November 6, 2007

<?php
$email = $_COOKIE['email'];
$sql = "SELECT username FROM players WHERE email='$email' ";
$sql = mysql_query($sql);
$row = mysql_fetch_assoc($sql);
$username = $row['username'];

if (!isset($username))  {

echo "you are not allowed to acces this page";
exit;
}
else 
{
    echo "Logged in as ".$username;
}
?>

trq · November 6, 2007

Post your current code.

Ads · November 6, 2007

main.php


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<link href="style1.css" rel="stylesheet" type="text/css" />
</head>

<body>
<?php 
include "include/db.php";
?>
<?php
$email = $_COOKIE['email'];
$sql = "SELECT username FROM players WHERE email='$email' ";
$sql = mysql_query($sql);
$row = mysql_fetch_assoc($sql);
$username = $row['username'];

if (!isset($username))  {

echo "you are not allowed to acces this page";
exit;
}
else 
{
    echo "Logged in as ".$username;
}
?>
</body>
</html>

login.php

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Login</title>
<link href="style1.css" rel="stylesheet" type="text/css" />
</head>

<body>
<form method="post" action="loginck.php" target="_parent">
<p align="center">
<span class="style2">Enter Email:</span> <br>
  <input type="text" name="email" id="email">
  <br>
  <span class="style2">Enter Passowrd:</span><br>
  <input type="password" name="password">
  <br>
  <input name="Submit" type="submit" class="top" value="Submit">
    </p>
<p align="center"> </p>
<p align="center">
  </div>
      <strong>Messages:</strong>
</p>
</p>
    <div align="center">Working on</div>
    
    
</body>
</html>

loginck.php

<?
session_start();
?>
<?php
//include "include/db.php";
?>
<!doctype html public "-//w3c//dtd html 3.2//en">

<html>

<head>
    <link href="style1.css" rel="stylesheet" type="text/css">
<title></title>

</head>

<body>
<?php
include "include/db.php";

$email = $_POST['email'];
$password = $_POST['password'];

$check = mysql_query("select * from players where email='$email'");
$check1 = mysql_query($check);
$row = mysql_fetch_assoc($check);

$db_user = $row['email'];
$db_password = $row['password'];



if (!$db_user) {
$message = "<head><link href=\"styles.css\" rel=\stylesheet\" type=\"text/css\" /></head>
		   <p class=\"errortext\"><strong>$email</strong> is not in the database...</p>";
	  
	   

}
// give error if user exists but wrong password
	else if (($db_user)&& ($password !== $db_password)) {
		$message = "<head><link href=\"styles.css\" rel=\stylesheet\" type=\"text/css\" /></head>
					<p class=\"errortext\"> Your password is wrong...</p>";



	}
	else if (($db_user) && ($password == $db_password)){
setcookie ("email",$email,+3600);
print "<script>";
print " self.location='main.php';"; 
print "</script>";
				}
		?>


</body>

</html>

farkewie · November 6, 2007

This may be it . its on logincheck.php

<?php

$check = mysql_query("select * from players where email='$email'");
$check1 = mysql_query($check);
$row = mysql_fetch_assoc($check);

?>

should be

<?php

$check = mysql_query("select * from players where email='$email'");
   if ($result = mysql_query($check)) {

      if ($row = mysql_fetch_assoc($result))

      }
   }
   else { 

    echo mysql_error();
   }
?>

Ads · November 6, 2007

<?php
      if ($row = mysql_fetch_assoc($result))

      }
?>

What goes in that statement?

I am alst getting this error:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Resource id #4' at line 1

farkewie · November 6, 2007


<?php

$check = mysql_query("select * from players where email='$email'");
   if ($result = mysql_query($check)) {

      if ($row = mysql_fetch_assoc($result)){

echo "user logged in";
      }
   }
   else { 

    echo mysql_error();
   }
?>

Ads · November 6, 2007

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Resource id #4' at line 1

Still get that error.

farkewie · November 6, 2007

can you configm what page this is on and try evhoes $email before the sql query?


echo $email;

Ads · November 6, 2007

can you configm what page this is on and try evhoes $email before the sql query?
echo $email;

it is on lohinck.php, and yes i can echo the email, and the password

farkewie · November 6, 2007


$check = "SELECT * FROM players where email='$email'";

Ads · November 6, 2007

on main.php. It does not let me acess the page. Even if i enter the right Login info.

Would someone be able to Give me. or Direct me to some login Code, that acctuly Works, and is easy to understand

farkewie · November 6, 2007

You are better off fixing this one as you are nearly there and can learn for next time.

if you look at the db in phpmyadmin does it have a field called username?

and how are the password storedplain text or encrypted?

Ads · November 6, 2007

I do have a feild called username, And They are just plain text.

farkewie · November 6, 2007

change the cookie to this it all i can think of. sorry


setcookie("email",$db_user, time()+3600);  /* expire in 1 hour */

Ads · November 6, 2007

change the cookie to this it all i can think of. sorry
setcookie("email",$db_user, time()+3600);  /* expire in 1 hour */

nope sorry still doesn;t work

I have run out of idea for this, and it proberly the most simply thing as well >.>...proberly a Missing Semi Colon

trq · November 6, 2007

Your login.php page can remain the same. However, here is an example of what your loginck.php should look like. You never actually set any $_SESSION variables, so there is no login.

<?php

 session_start();

 include "include/db.php";

 if (isset($_POST['Submit'])) {
   $email = mysql_real_escape_string($_POST['email']);
   $password = mysql_real_escape_string($_POST['password']);
   $sql = "SELECT username FROM players WHERE email='$email'";
   if ($result = mysql_query($sql)) {
     if (mysql_num_rows($result)) {
       $row = mysql_fetch_assoc($result);
       $_SESSION['username'] = $row['username'];
       header("Location: main.php");
     }
   }
 }

?>

Now, your main.php should look like....

<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
 <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
 <title>Untitled Document</title>
 <link href="style1.css" rel="stylesheet" type="text/css" />
</head>
<body>
<?php

 if (!isset($_SESSION['username'])) {
   echo "<p>you are not allowed to acces this page</p>";
 } else {
   echo "<p>Logged in as {$_SESSION['username']}</p>";
 }

?>
</body>
</html>

Hope that helps.

farkewie · November 6, 2007

ok just going to check the really basics...lol

when you fill out the login for your entering your email address not username?

you dont have any special charsin the password

the code isnt miss types because we are not getting errors. its doing what its supposed to do and not let you in if it cant authenticate..

double check everything look at the querys and make sure you are passing the right details to them.

Ads · November 6, 2007

usesing thorpe's code i get this error

Warning: Cannot modify header information - headers already sent by (output started at C:\wamp\www\Athina\loginck.php:19) in C:\wamp\www\Athina\loginck.php on line 32

trq · November 6, 2007

make sure there is no output (or whitespace) in your db.php file.

Ads · November 6, 2007

<? 
$hostname="localhost"; 
$mysql_login="USERNAME"; 
$mysql_password="PASSWORD"; 
$database="athina"; 

if (!($db = mysql_connect($hostname, $mysql_login , $mysql_password))){ 
  die("Can't connect to mysql.");     
}else{ 
  if (!(mysql_select_db("$database",$db)))  { 
    die("Can't connect to db."); 
  } 
} 
?>

that is my db.php, i can;t see any problem with it.

trq · November 6, 2007

Is there any blank lines outside of the <? ?> tags?

ps: You should always use <?php ?> tags.

Ads · November 6, 2007

No Blank Spaces

trq · November 6, 2007

Well, there is output somewhere, you'll need to make sure there is no output (including any whitespace) prior to any session_start(); calls.

Sign In

[SOLVED] Login not working

Recommended Posts

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Link to comment

Share on other sites

Archived

Important Information