Questions about using post with PHP and getting the data back

[dooh]

Hello,

 

I am posting numbers.

 

the name = number for all names = ...and the value = different numbers eg...fx1005 or dx33 or sx9

the fx, dx, sx  is just added to the number and it tells me what to do with the value when I get it

 

here is the code I wrote to get the values back:

 

$numbers_received = array();

$numsA = array();

 

$counter = 0;

 

$numbers_received = $_POST['number'];

 

foreach($numbers_received as $value) {

$numsA[$counter] = "$value";

$counter = $counter + 1;

}

 

and now to look at what I received..

 

 

echo $numsA[4];

 

 

 

I get this error in the log: invalid argument supplied foreach()

 

It leads me to believe that what was posted was not an array. Is this true?

 

Is there a way for me to do this?

 

 

 

This was just a test sending 10 numbers and I had hoped that it would echo a result..it did not

 

I can do this a long way but, using perl reasoning fIigured something like this could be done in php too.. with fewer keystrokes

 

I'm new to php so don't laugh.

 

 

 

Andrew

 

 

 

 

 

 

 

 

 

 

[kenrbnsn]

Please post your form source.

[dooh]

Here ya go,

 

<form action = "$self" method = "post">

<input type="hidden" name="number" value="dx2201">

<input type="hidden" name="number" value="dx108">

<input type="hidden" name="number" value="sx9">

<input type="hidden" name="number" value="fx1">

<input type = "submit" value = "Submit">

</form>

 

Andrew

[gin]

You know, I'm not understanding what exactly you're trying to accomplish here....

 

Anyway, you've got 1 variable (one!) in your form. How does your form pass the information to $numbers_received & $numsA? You're getting the error because those two variables don't have any information at all. Incidentally, $value up there would hold "dx2201" not "2201" like I suspect you're hoping. All that code up there does is copy the info from one array to another in a very difficult fashion.

 

Wouldn't it be easier to transfer your information in separated arrays? Something that would result in:

 

$dx = array (2201, 108);

$sx = array (9);

[kenrbnsn]

In order to pass multiple values using the same name, you need to make that name an array:

<form action = "$self" method = "post">
   <input type="hidden" name="number[]" value="dx2201">
   <input type="hidden" name="number[]" value="dx108">
   <input type="hidden" name="number[]" value="sx9">
   <input type="hidden" name="number[]" value="fx1">
   <input type = "submit" value = "Submit">
</form>  

 

To reference the returned values, use "$_POST['number'][0]"  through "$_POST['number][3]".

 

Ken

[dooh]

Thank you kenrbnsn,

 

Here is your answer back...

 

            $number1_received = $_POST['number'][0];

$number2_received = $_POST['number'][1];

$number3_received = $_POST['number'][2];

 

echo $number1_received;

echo "\n";

echo $number2_received;

echo "\n";

echo $number3_received;

echo "\n";

 

but...is this what you meant?

 

 

Andrew