jwwceo Posted November 21, 2007 Share Posted November 21, 2007 I have another tricky query which I can't seem to get working: There are 4 tables, with various links to one another. I want to update the value image_path in one table, based on the values from 2 other tables. The two values for this particluar query are productid: 16150 option_name: Black Here is the code I have so far: Thanks!!! UPDATE xcart_images_W SET image_path = 'test.png' INNER JOIN xcart_variants.variantid ON xcart_variant_items.variantid INNER JOIN xcart_variant_items.optionid ON xcart_class_options.optionid INNER JOIN xcart_variants.variantid ON xcart_images_W.id WHERE xcart_variants.productid = '16150' AND xcart_class_options.option_name = 'Black' Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/ Share on other sites More sharing options...
fenway Posted November 21, 2007 Share Posted November 21, 2007 This is just like your other post... there's no "first" table. Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-395830 Share on other sites More sharing options...
jwwceo Posted November 21, 2007 Author Share Posted November 21, 2007 I don't know what you mean by "first table"??? The table I am trying to update is xcart_images_W. The field in that table is image_path. Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-395855 Share on other sites More sharing options...
fenway Posted November 21, 2007 Share Posted November 21, 2007 You've interspersed your SET in the middle of a JOIN! Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-396010 Share on other sites More sharing options...
jwwceo Posted November 21, 2007 Author Share Posted November 21, 2007 I guess I don't know enough about JOINS to understand what that means? Any idea how to correctly write this syntax??? Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-396089 Share on other sites More sharing options...
fenway Posted November 21, 2007 Share Posted November 21, 2007 Move the SET after the last join before WHERE. Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-396261 Share on other sites More sharing options...
jwwceo Posted November 21, 2007 Author Share Posted November 21, 2007 I made the changes you said and I get this error. I really appreciate the help with this.. #1066 - Not unique table/alias: 'variantid' Here's what I used... UPDATE xcart_images_W INNER JOIN xcart_variants.variantid ON xcart_variant_items.variantid INNER JOIN xcart_variant_items.optionid ON xcart_class_options.optionid INNER JOIN xcart_variants.variantid ON xcart_images_W.id SET image_path = 'test.png' WHERE xcart_variants.productid = '16150' AND xcart_class_options.option_name = 'Black' Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-396307 Share on other sites More sharing options...
jwwceo Posted November 21, 2007 Author Share Posted November 21, 2007 I got it working using this. I was failing to list all the tables in the UPDATE line, even if they aren't being updated UPDATE xcart_images_W, xcart_variants, xcart_variant_items, xcart_class_options SET xcart_images_W.image_path = 'test1.png' WHERE xcart_variants.variantid = xcart_variant_items.variantid AND xcart_variant_items.optionid = xcart_class_options.optionid AND xcart_variants.variantid = xcart_images_W.id AND xcart_variants.productid = '16150' AND (xcart_class_options.option_name = 'Black' OR xcart_class_options.option_name = 'Gold' OR xcart_class_options.option_name = 'Navy') Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-396329 Share on other sites More sharing options...
teng84 Posted November 21, 2007 Share Posted November 21, 2007 ignore topic solved Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-396333 Share on other sites More sharing options...
fenway Posted November 22, 2007 Share Posted November 22, 2007 It may be "solved", but the issue was joining the same table twice with an alias on different conditions. Quote Link to comment https://forums.phpfreaks.com/topic/78212-solved-even-tricker-one/#findComment-396694 Share on other sites More sharing options...
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