[SOLVED] Me again!! Query Help Please.

[d_barszczak]

Hi all,

 

Just when im getting to grips with this mysql business i have another problem ???

 

The following query works:

SELECT MAX(`order`) as `MAXorder` FROM `nav_directory`;

 

which return MAXorder = 10.

 

i would like it to return the tag also

tag, MAXorder

page1, 10

 

My Solution to this was:

SELECT `tag`, MAX(`order`) as `MAXorder` FROM `nav_directory` GROUP BY order;

 

But that lists all the tags. Can anyone help???

[rajivgonsalves]

something like the following should work but not too sure

 

SELECT `tag`, MAX(`order`) as `MAXorder` FROM `nav_directory` GROUP BY order having order=MAX(`order`) ;

 

[d_barszczak]

Thanks but that gives me the same result.

 

I want the highest value of `order` and the `tag` that accompanies it.

 

Thanks.

[fenway]

The robust way to do this is as follows (untested):

 

SELECT n.tag, n.order
FROM nav_directory AS n
JOIN 
( SELECT MAX(order) as MAXorder FROM nav_directory ) AS sub ON ( sub.MAXorder = n.order )

Of course, you could add as many conditions as you wanted.  Don't forget about the boundary case; you may want an order by, too.

[d_barszczak]

I used this in the end.

 

SELECT `order`, `tag` FROM `nav_directory` ORDER BY `order` desc LIMIT 1;

 

This alway returns the highest value with the tag.

 

EDIT: Also gone and named `order` which is a reserved word. Need to be more careful with my naming stratergy.