Chris McGee Posted December 5, 2007 Share Posted December 5, 2007 When I put my username and password in the fields and then submit I get the fallowing error... Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in /home/purseati/public_html/Connections/users.php on line 58 Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home/purseati/public_html/Connections/users.php on line 63 Does anyone know what to do? Link to comment https://forums.phpfreaks.com/topic/80223-login-php-quick-question/ Share on other sites More sharing options...
trq Posted December 5, 2007 Share Posted December 5, 2007 Post your code! Link to comment https://forums.phpfreaks.com/topic/80223-login-php-quick-question/#findComment-406628 Share on other sites More sharing options...
Chris McGee Posted December 5, 2007 Author Share Posted December 5, 2007 <?php require_once('Connections/users.php'); ?> <?php $host="localhost"; $user="purseati_XJ5014"; $pass="mcgee87"; $db="purseati_userlogin"; $connection = mysql_connect($host,$user,$pass)or die ('Unable to connect'); mysql_select_db($db) or die ('Unable to select DB');?> <?php if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? "'" . doubleval($theValue) . "'" : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } ?> <?php // *** Validate request to login to this site. if (!isset($_SESSION)) { session_start(); } $loginFormAction = $_SERVER['PHP_SELF']; if (isset($_GET['accesscheck'])) { $_SESSION['PrevUrl'] = $_GET['accesscheck']; } if (isset($_POST['usernameText'])) { $loginUsername=$_POST['usernameText']; $password=$_POST['passwordText']; $MM_fldUserAuthorization = ""; $MM_redirectLoginSuccess = "contact.html"; $MM_redirectLoginFailed = "home.html"; $MM_redirecttoReferrer = false; mysql_select_db($database_users, $users); $LoginRS__query=sprintf("SELECT username, password FROM users WHERE username=%s AND password=%s", GetSQLValueString($loginUsername, "text"), GetSQLValueString($password, "text")); $LoginRS = mysql_query($LoginRS__query, $users) or die(mysql_error()); $loginFoundUser = mysql_num_rows($LoginRS); if ($loginFoundUser) { $loginStrGroup = ""; //declare two session variables and assign them $_SESSION['MM_Username'] = $loginUsername; $_SESSION['MM_UserGroup'] = $loginStrGroup; if (isset($_SESSION['PrevUrl']) && false) { $MM_redirectLoginSuccess = $_SESSION['PrevUrl']; } header("Location: " . $MM_redirectLoginSuccess ); } else { header("Location: ". $MM_redirectLoginFailed ); } } ?> Link to comment https://forums.phpfreaks.com/topic/80223-login-php-quick-question/#findComment-406632 Share on other sites More sharing options...
aqlx86 Posted December 5, 2007 Share Posted December 5, 2007 may be you dont have a valid mysql connection resource.. double check host,username,password, db Link to comment https://forums.phpfreaks.com/topic/80223-login-php-quick-question/#findComment-406636 Share on other sites More sharing options...
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