Another WTF Parse error.

[hellonoko]

I am now getting a similar parse error.

The below code worked once. Then I tried to add additional image/types to the upload script in the if statement and it failed. Even after removing new code.

 

Error:

Parse error: syntax error, unexpected '[', expecting ')' in C:\www\idea\imagebox\add_image.php on line 61

 

Line 61 Is first line in upload function:

 

function upload_image($_FILES['imagefile'],$image_to_thumbnail)

 

Full code:

<style type="text/css">
<!--
input
{
color: #000000;
background: #FFFFFF;
border: 1px solid #000000;
font-size: 10px;
font-family: Arial, Helvetica, sans-serif;
}

.input_images
{
vertical-align:middle;
color: #000000;
background: #FFFFFF;
border: 0px solid #FFFFFF;
font-size: 10px;
font-family: Arial, Helvetica, sans-serif;
}

-->
</style>

<form name="copyimage" method="post" action="copy.php" enctype="multipart/form-data">
<input name="action" type="hidden" value="copy" />
<input name="url" type="text" value="" size="100"><input name="filename" type="text" value="" size="20">
<input name="action" type="hidden" value="copy">
<input type="image" class="input_images" src="../images/add.png" alt="Add">
</form> 

<form name="uploadimage" method="post" action="upload.php" enctype="multipart/form-data">
<input name="imagefile" type="file" size="100">
<input name="Upload" type="submit" value="upload" />
</form>


<?php


$action = $HTTP_POST_VARS[action];

if ($action == "copy")
{
	copy_image( $file_name );
}

if ($action == "upload")
{
	upload_image( $imagefile );
}



?>

<?php

//upload image function

function upload_image($_FILES['imagefile'],$image_to_thumbnail)
{
ini_set('display_errors', 1);
error_reporting(E_ALL);

//$submit = $_POST['Submit'];
if (empty($_FILES['imagefile']))
	{
		echo "<br><br>";
		echo "Please choose a image to upload...";
		die;
	}


if(!empty( $_FILES['imagefile'] ))
{

	//If the Submitbutton was pressed do:

	if ($_FILES['imagefile']['type'] == "image/jpeg")
	{

		$_FILES['imagefile']['name'] = str_replace(" ", "_", $_FILES['imagefile']['name']);

		copy ($_FILES['imagefile']['tmp_name'], "images/full/".$_FILES['imagefile']['name']) or die ("Could not copy"); 

		echo "<br><br>"; 
        	
		echo "<b>File Uploaded...</b>"; 
        }

 	else 
 	{
            echo "<br><br>";
            //echo "Could Not Copy... (".$_FILES['imagefile']['name'].")<br>";
		echo "Could Not Copy... <br>";
		die;
     	}
}   

echo "<br>";
$image_to_thumbnail = $_FILES['imagefile']['name'];
//echo $image_to_thumbnail;

include "resize_image.php";

echo "image uploaded";
echo "<br>";
echo "<img src=images/thumbs/t_".$image_to_thumbnail." />";
echo "<br>";
echo "<img src=images/full/".$image_to_thumbnail." />";
}
?> 

<?php

//function to copy image
function copy_image($url, $file_name, $image_to_thumbnail)
{

	$url = $HTTP_POST_VARS[url];
	$file_name = $HTTP_POST_VARS[filename];


	if ($url == "")
	{
		echo "You must enter a url. ";
		echo "<meta http-equiv='REFRESH' content=3;url=add_image.php>";
	}

	if ($file_name == "")
	{
		echo "You must name the file. ";
		echo "<meta http-equiv='REFRESH' content=3;url=add_image.php>";
		exit();
	}

	if ($url != "")
	{
		copy( $url, "images/full/".$file_name );

		$image_to_thumbnail = $file_name;

		include "resize_image.php";

		echo "image coppied";
		echo "<br>";
		echo "<img src=images/thumbs/t_".$image_to_thumbnail." />";
		echo "<br>";
		echo "<img src=images/full/".$image_to_thumbnail." />";

	}
}
?>

 

Thanks in advance.

[trq]

You need to read up on functions, you cannot name an argument definition as an array element.