[SOLVED] Can't figure out pagination

[forumnz]

I have 11 rows in my db, all including the letter a, which I searched for. The results page says displaying 1-10 of 11, so it has found them all. My results page has a limit of 10 rows and has a link for the next 10.

 

When I click that link, it does not load 11 etc, just 1-10. Please help this is so frustrating.

 

Thanks,

Sam.

 

Code:

<?php

  // Get the search variable from URL

  $var = @$_GET['q'] ;
  $trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$limit=10; 

// check for an empty string and display a message.
if ($trimmed == "")
  {
  echo "<p>Please enter a search...</p>";
  exit;
  }

// check for a search parameter
if (!isset($var))
  {
  echo "<p>We dont seem to have a search parameter!</p>";
  exit;
  }

//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","aa","aa"); //(host, username, password)

//specify database ** EDIT REQUIRED HERE **
mysql_select_db("aa") or die("Unable to select database"); //select which database we're using

// Build SQL Query  
$query = "select * from clickme where keywords LIKE '%$trimmed%' OR buzzname LIKE '%$trimmed%'  
  order by keywords"; // EDIT HERE and specify your table and field names for the SQL query

$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);

// If we have no results, offer a google search as an alternative

if ($numrows == 0)
  {
  echo "<h4>Results</h4>";
  echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";

// google
echo "<p>Please click here to suggest a business.</p>";
  }

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
  $query .= " limit $s,$limit";
  $result = mysql_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";

// begin to show results set
echo "Results<br><br>";
$count = 1 + $s ;

// now you can display the results returned
  while ($row= mysql_fetch_array($result)) {
  $title = $row["buzzname"];
    $titled = $row["buzzdesc"];

  echo "$count)  $title<br> $titled<br><br>" ;
  $count++ ;
  }

$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< 
  Prev 10</a>&nbsp ";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$limit) {
  // has remainder so add one page
  $pages++;
  }

// check to see if last page
  if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$limit;

  echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>";
  }

$a = $s + ($limit) ;
  if ($a > $numrows) { $a = $numrows ; }
  $b = $s + 1 ;
  echo "<p>Showing results $b to $a of $numrows</p>";
  
?>

[trq]

For starters, $s is not defined anywhere in your script.

[forumnz]

Ok thanks how should I define it?

[trq]

Its in $_GET.

[Ken2k7]

Its in $_GET.

How did you know that!?  ???

[forumnz]

Thanks thorpe!

 

Its in $_GET.

How did you know that!?  ???

Because he saw the Next 10 link at the bottom.

 

Sam.