rpjd Posted December 29, 2007 Share Posted December 29, 2007 I am trying to verify that a table, which has just 1 column has at least 1 entry. My code is: $link = mysql_connect($dbServer, $dbUser, $dbPass) or die ("Could not connect"); print "Connected successfully<br>"; mysql_select_db("$dbName", $link) or die("Could not select database"); print "Database selected successfully<br>"; $query = mysql_query("select * from mobiles", $link); $rows = mysql_num_rows($query); as can be seen, I am using the result of the select query $query as the resourse for the mysql_num_rows() function, yet I am getting the above warning. Can anyone explain why I am getting this warning? Link to comment https://forums.phpfreaks.com/topic/83605-mysql_num_rows-supplied-arguement-is-not-a-valid-myqsl-result-resource/ Share on other sites More sharing options...
kenrbnsn Posted December 29, 2007 Share Posted December 29, 2007 Put a "or die" clause on the mysql_query() function. Ken Link to comment https://forums.phpfreaks.com/topic/83605-mysql_num_rows-supplied-arguement-is-not-a-valid-myqsl-result-resource/#findComment-425351 Share on other sites More sharing options...
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