Jump to content


Photo

String Question


  • Please log in to reply
2 replies to this topic

#1 Mateobus

Mateobus
  • Members
  • PipPipPip
  • Advanced Member
  • 95 posts

Posted 28 April 2006 - 05:18 AM

I just want to do a Boolean check of a string that returns true if the last two characters of the string are upper case and false otherwise. Thanks.

#2 toplay

toplay
  • Staff Alumni
  • Advanced Member
  • 973 posts

Posted 28 April 2006 - 06:00 AM

You can do it with preg_match() too, but this is probably one of the easiest ways:
$text = 'abCD';

// Make sure the string is always 2 characters or more otherwise substr() returns false
if (ctype_upper(substr($text, -2)) {
       echo "The string $text last 2 characters consists of uppercase letters.\n";
   } else {
       echo "The string $text last 2 characters do not consist of uppercase letters.\n";
   }


#3 .josh

.josh
  • Staff Alumni
  • .josh
  • 14,871 posts

Posted 28 April 2006 - 06:02 AM

<?php
$blah = "abcdef";

$test = substr($blah, -2);
if (ctype_upper($test)) {
echo "letters are uppercase";
}
else { echo "letters are not uppercase"; }
?>

edit: gah! you beat me :(
Did I help you? Feeling generous? Buy me lunch! 
Please, take the time and do some research and find out how much it would have cost you to get your help from a decent paid-for source. A "roll-of-the-dice" freelancer will charge you $5-$15/hr. A decent entry level freelancer will charge you around $15-30/hr. A professional will charge you anywhere from $50-$100/hr. An agency will charge anywhere from $100-$250/hr. Think about all this when soliciting for help here. Think about how much money you are making from the work you are asking for help on. No, we do not expect you to pay for the help given here, but donating a few bucks is a fraction of the cost of what you would have paid, shows your appreciation, helps motivate people to keep offering help without the pricetag, and helps make this a higher quality free-help community :)




0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users