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I have some stats for an irc server, which are stored in a mysql database.

 

Table looks like:

User | Lines | Characters

 

When a user types - `mystats, it retrieves his information from the mysql database alll good

 

It will then display - *user* you have written X lines and X characters at an average of X.XX characters per line.

 

That works perfectly fine. What i would also like it to do is say Your rank is: X

 

but i have no idea where to start? hints or tips anyone

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ordering by lines written

 

yes it stores and yes it works, when someone types a message in irc, the php bot will pick it up find the user who wrote it and add 1 to there line count.

 

Pretty simple and it works, i have made a top 10 ranking which works perfectly well, but i would just like it to display the one rank for the person

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https://forums.phpfreaks.com/topic/86406-ranks/#findComment-441529
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Think this might work.  Barand will be of more help as he is scary good at SQL...

 

SELECT COUNT(id) AS rank
FROM (
	SELECT (characters / lines) AS avg_chars
	FROM table_name
)
WHERE avg_chars > (
SELECT (characters / lines)
FROM table_name
WHERE username = 'user'
)

 

May be thrown off by ties.

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https://forums.phpfreaks.com/topic/86406-ranks/#findComment-441530
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well u got a top 10 rank u are pretty much there just use a loop to find the user in the listing whilst u increamment a var that will give them there position (just remember before you show them their ranks do $i+1 or else it will show them one under than what they actually are)

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https://forums.phpfreaks.com/topic/86406-ranks/#findComment-441533
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yeah ok well for the top 10 ive got

 

$rank = 1;

 

while ... {

$rank $user($lines)

$rank++;

}

 

so that works perfectly well

 

but when trying to do this for individual rank, would i have to make a completely different sql query, because right now i am just going select * from stats where user=$user which will only give me the info for that person not everyone else..

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https://forums.phpfreaks.com/topic/86406-ranks/#findComment-441539
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ok im trying but really getting nowhere :S

 

$query = "SELECT count(*) as rank from (select * from stats where written > (select written from stats where user='Kingy') order by written desc)";

 

$result = mysql_query($query) or die(mysql_error());

 

that code gives the error - Every derived table must have its own alias

 

also how would i display the above??

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https://forums.phpfreaks.com/topic/86406-ranks/#findComment-441631
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OK ill try i..

 

$query = 'select * from user oder by rank desc;

$query =mysql_query($query);

while($row = mysql_fetch_array($query )){

    ++$x;

  if ($row[id] == yourid){

    echo 'rank'.$x;   

    break;

  }

}

 

this will echo the rank of specific user

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