[SOLVED] PHP var not working

[$username]

Hello All,

    So I am working on making some code a var in PHP but it will not load correctly (not at all)

If some one could tell me if this can be done with php.

$AccountList =	while($row = mysql_fetch_array($query)) {
		"<table>
			<tr>
				<th><strong>Account ID:</strong></th>
				<th><strong>Account Name</strong></th>
			</tr>
				<tr>"
				"<th><a href=\"viewaccount.php?AccNum=".$row["AccountNumber"]."\" title=\"".$row["AccountID"]."\">".$row["AccountID"]."</a></th>"
				"<th>".$row['AccountName']."</th>
			</tr>
		</table>"};

Thank you,

Brett

[kenrbnsn]

You can not have a while statement as you have shown it. What do you want to do exactly?

 

Ken

[$username]

I would like to make all that one var so that I can call it later when needed.

 

Brett

[Bauer418]

$accountList = '';
while ($row = mysql_fetch_array($query)) {
   $accountList .= "<table>
			<tr>
				<th><strong>Account ID:</strong></th>
				<th><strong>Account Name</strong></th>
			</tr>
				<tr>
				<th><a href=\"viewaccount.php?AccNum=".$row["AccountNumber"]."\" title=\"".$row["AccountID"]."\">".$row["AccountID"]."</a></th>
				<th>".$row['AccountName']."</th>
			</tr>
		</table>";
}
print $accountList;

[$username]

Wow Bauer418 for only 3 post you are pretty good.

 

Thank you that fixed me up.

[Bauer418]

I have gone through three accounts on this site already.  I'm well over a cumulative of 5,000 by now.  Anyways, if this solved your issue, make sure to click the solved button and mark this post as solved.