[SOLVED] dynamic function arguments

[taith]

trying to pass dynamic function arguments from one function into another...

 

<?
function f($f){
$a=func_get_args();
unset($a[0]);
return $f(implode(', ',$a));
}

for($i=0; $i<20; $i++){
echo '<br>'.f(rr,'0'.rand(1,99999),4);
}
?>

 

which works all well and good... however, the ,4 is added onto the $a as tho it were part of the same string, and i want it segregated(second argument in my rr function).... any ideas?

 

that'd output somin like

 

012195, 4
018554, 4
061523, 4
043335, 4
022405, 4
095647, 4

[Stooney]

The function f() only accepts 1 argument.  You would need to add more.  So if you want to do f(rr, '0'.rand(1,99999), 4) then you should declare the function like function f($arg1, $arg2, $arg3)  Hope it makes sense

[taith]

yes and no... f() only recognizes one static argument... however, the  $a=func_get_args(); returns ALL arguments... even if they were not declared...