Jump to content

Recommended Posts

I have a query to pull info by owner, pet id and amount of books they've read but I can't get it to display correctly on a web page. Here's my query that I currently have:

 

$x = 1;
$query = "SELECT DISTINCT `user_pets2`.`owner` , `read2`.`pet_id` , `user_pets2`.`id` , MAX( `user_pets2`.`book_count` ) AS amount
FROM `read2` , `user_pets2` 
WHERE `read2`.`pet_id` = `user_pets2`.`id` 
GROUP BY `user_pets2`.`owner` 
ORDER BY `amount` DESC 
LIMIT 25 "; 
$result= mysql_query($query) or die ("Error in query " . mysql_error()); //whats the error??  while($row = mysql_fetch_assoc($result))
{
  $username = $row['id'];
$number = $row['amount'];
$pets2 = fetch("SELECT * FROM user_pets2 WHERE id = '$username' AND game = '1'");
$top .= " <tr><td width=33% valign=middle><div align=center><b><font face=verdana color=#0047BE>$x.</b></font></div></td><td width=33% valign=middle><A href=user_pets.php?game=1&id=$username><font face=verdana color=#0047BE>$pets2[name]</a></td><td width=33% valign=middle><div align=middle><font face=verdana color=#0047BE>$number</font></div></td></tr>";
$x++;
} 

Link to comment
https://forums.phpfreaks.com/topic/89327-solved-help-please/
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.