[SOLVED] Work out a percentage ... but within min or max range

[jimbob-2k7]

Hi All,

 

What I am trying to do is this:

 

1) We start off with a price, we will say £40.

 

2) Then work out what 10% of the price ... so that will be £4.

 

3) That value then must be between a min (£3) and max (£6) value.

 

So £4 will be fine because it's between £3 and £6. But if we start off with £80 (then 10%, so it will be £ £8 is greater than the max vaule, so set it to the max value.

 

I hope you guys get what I am trying to do.

 

Cheers,

 

Jim

[PHP Monkeh]

<?php

$min = 3;
$max = 6;
$price = 80;

$newPrice = $price/10; // Here's your percentage

if($newPrice > $max) {

$max = $newPrice;

}

?>

 

No need to check whether it falls within the range is there?

[trq]

Its pretty simple math.

 

<?php

 $min = 3;
 $max = 6;
 $price = 40;
 $result = $price/10;
 if ($result < $min || $result > $max) {
   $result = $max;
 }

 echo $result;

?>

[pdkv2]

did you mean the board should write the script according to your requirement specifications ?

 

it all about the if and elase

[jimbob-2k7]

Wow thanks for the quick reply.

 

What do we do about the lower end ... so anything lower then the £3 will be £3.

 

Its nice to see peoples script and then learn from it 

 

Cheers.

[PHP Monkeh]

You want anything lower than £3 to be set to £3?  If you use my code it'll stay as £3... if what you meant was:

 

If it's lower than the min price, set the min price to the new value, do this:

 

<?php

$min = 3;
$max = 6;
$price = 80;

$newPrice = $price/10; // Here's your percentage

if($newPrice > $max) {

$max = $newPrice;

} else if($newPrice < $min) {

$min = $newPrice;

}

?>

 

Voila

[jimbob-2k7]

YAY! that worked thanks alot