[SOLVED] If Statement $_GET Var Links With Functions

[Hepp]

To answer your question, yes I read the FAQs, and there was a Select Case example there.

 

I've been coding for 3+ years now, but this is angering me.

 

Snippet of code:

 

<?php

function aboutUs($page) {

echo "This is the <b>about</b> section.";

}

if (isset($_GET['page'])) {

$page = ($_GET['page']);

if ($page[0] == "aboutUs") { 

aboutUs(); 

} else {

echo "";

}

}

?>

<a href=static.php?page=aboutUs>About</a>

 

I've been trying to get that to work all day. Is there something I am overlooking, doing wrong, or forgetting?

 

Bleh I need sleep 

 

Thanks so much.

-Hepp

[pocobueno1388]

You never told us what you were trying to do, or what the problem was.

[Hepp]

Hey man, thanks for replying.

 

I quickly threw it in the title - apologies.

 

I'm trying to have a page, and when the link is clicked (bottom of code), it pulls out the function using $_GET because I'm looking to make many of these.

 

And the problem is that the text doesn't appear from the function when the link is clicked.

 

Thanks.

-Hepp

[haku]

I still don't really get what your problem is.

 

But I see a couple problems:

 

1) you are referring to $page both as a single variable, and then as an array later on.

 

2) The function aboutUs($page) calls for the variable $page, but you aren't passing it to the function when you call it.

 

Don't know if thats where your problem is, but y8ou can try to fix those things and see what happens.

[Hepp]

I still don't really get what your problem is.

 

Don't know if thats where your problem is, but y8ou can try to fix those things and see what happens.

 

The problem is that when you click the link, it does not display the code from the function like I've been trying to get it to, you know?

 

2) The function aboutUs($page) calls for the variable $page, but you aren't passing it to the function when you call it.

 

But the function calling the variable, I removed it. I tried something earlier, forgot to get rid of it.

 

Here's the revised code:

 

<?php

function aboutUs() {

echo "This is the <b>about</b> section.";

}

if (isset($_GET['page'])) {

$page = ($_GET['page']);

if ($page[0] == "aboutUs") { 

aboutUs(); 

} else {

echo "";

}

}

?>

<a href=static.php?page=aboutUs>About</a>

 

1) you are referring to $page both as a single variable, and then as an array later on.

 

Can you not refer to $page as a single and then to an array? I couldn't think of another way to do this.

 

Thanks man.

-Hepp

[kenrbnsn]

You want the "if" statement to be

<?php
if ($page == "aboutUs") { 
aboutUs(); 
}
?>

 

Ken

[Hepp]

Ken,

 

I LOVE YOU. THANK YOU.

 

So simple, yet I need sleep.

 

Thanks buddy.

 

Revised correct code for anyone who is looking:

 

<?php

function aboutUs() {

echo "This is the <b>about</b> section.<p>";

}

function otherPage() {

echo "This is the <b>other</b> section.<p>";

}

if (isset($_GET['page'])) {

$page = ($_GET['page']);

if ($page == "aboutUs") { 

aboutUs(); 

} elseif ($page == "otherPage") {

otherPage();

} else {

echo "";

}

}

?>

<a href=static.php?page=aboutUs>About</a>
<a href=static.php?page=otherPage>Other</a>

 

Thanks again Ken =)

 

-Hepp