Jump to content

Login check account active or not


cozzy1984

Recommended Posts

Have been using a script i got from evolt.com for a login and modified it slightly, and it works. Although i am now looking to check it the account is active or not and if so login and if not display a message. Have added 'active' field to database which is an int of deafult '0'.

 

here is my code:

<?php

$loginerror = "";

/**
* Checks whether or not the given username is in the
* database, if so it checks if the given password is
* the same password in the database for that user.
* If the user doesn't exist or if the passwords don't
* match up, it returns an error code (1 or 2). 
* On success it returns 0.
*/
function confirmUser($username, $password){
   global $conn;
   /* Add slashes if necessary (for query) */
   if(!get_magic_quotes_gpc()) {
$username = addslashes($username);
   }

   /* Verify that user is in database */
   $q = "select password from users where username = '$username'";
   $result = mysql_query($q,$conn);
   if(!$result || (mysql_numrows($result) < 1)){
      return 1; //Indicates username failure
   }

   /* Retrieve password from result, strip slashes */
   $dbarray = mysql_fetch_array($result);
   $dbarray['password']  = stripslashes($dbarray['password']);
   $password = stripslashes($password);

   /* Validate that password is correct */
   if($password == $dbarray['password']){
      return 0; //Success! Username and password confirmed
   }

   else{
      return 2; //Indicates password failure
   }
}

/**
* checkLogin - Checks if the user has already previously
* logged in, and a session with the user has already been
* established. Also checks to see if user has been remembered.
* If so, the database is queried to make sure of the user's 
* authenticity. Returns true if the user has logged in.
*/
function checkLogin(){
   /* Check if user has been remembered */
   if(isset($_COOKIE['cookname']) && isset($_COOKIE['cookpass'])){
      $_SESSION['username'] = $_COOKIE['cookname'];
      $_SESSION['password'] = $_COOKIE['cookpass'];
   }

   /* Username and password have been set */
   if(isset($_SESSION['username']) && isset($_SESSION['password'])){
      /* Confirm that username and password are valid */
      if(confirmUser($_SESSION['username'], $_SESSION['password']) != 0){
         /* Variables are incorrect, user not logged in */
         unset($_SESSION['username']);
         unset($_SESSION['password']);
         return false;
      }
      return true;
   }
   /* User not logged in */
   else{
      return false;
   }
}

/**
* Determines whether or not to display the login
* form or to show the user that he is logged in
* based on if the session variables are set.
*/
function displayLogin(){
global $loginerror;
   global $logged_in;
   if($logged_in){
      echo "<div id='userbox'>
    <h2 class='first'>Welcome $_SESSION[username],</h2>
    <ul>
<li><a href=''>My Ads</a></li>
<li><a href=''>Create Advert</a></li>
<li><a href=''>My Details</a></li>
      <li class='logout'><a href='logout.php'>Logout</a></li>
    </ul>
    </div>";
     
   }
   else{

include "loginform.php";
echo "<p class='error' style='color:#d72b1a; font: bold 11px/1.2 Arial, Helvetica, sans-serif; text-align:center;'>$loginerror</p>";

   }
}


/**
* Checks to see if the user has submitted his
* username and password through the login form,
* if so, checks authenticity in database and
* creates session.
*/
if(isset($_POST['sublogin'])){
$_POST['user'] = trim($_POST['user']);
   /* Checks that username is in database and password is correct */
   $md5pass = md5($_POST['pass']);
   $result = confirmUser($_POST['user'], $md5pass);

   /* Check that all fields were typed in */
   if(!$_POST['user'] || !$_POST['pass']){
$loginerror = "You didn't fill in a required field";
   }
   /* Spruce up username, check length */
   else if(strlen($_POST['user']) > 30){
$loginerror = "Username is longer than 30 characters";
         }

   /* Check error codes */
   else if($result == 1){
$loginerror = "Username doesn't exist";
        }
   else if($result == 2){
$loginerror = "Incorrect Password";
       }

   /* Username and password correct, register session variables */
   $_POST['user'] = stripslashes($_POST['user']);
   $_SESSION['username'] = $_POST['user'];
   $_SESSION['password'] = $md5pass;

   /**
    * This is the cool part: the user has requested that we remember that
    * he's logged in, so we set two cookies. One to hold his username,
    * and one to hold his md5 encrypted password. We set them both to
    * expire in 100 days. Now, next time he comes to our site, we will
    * log him in automatically.
    */
   if(isset($_POST['remember'])){
      setcookie("cookname", $_SESSION['username'], time()+60*60*24*100, "/");
      setcookie("cookpass", $_SESSION['password'], time()+60*60*24*100, "/");
   }


}

/* Sets the value of the logged_in variable, which can be used in your code */
$logged_in = checkLogin();

?>

 

was thinking of adding:

$q = "select password,active from users where username = '$username'";

 

and then

 

  else if(active=='0'{

      return 3; //Indicates inactive account

  }

 

and of course the error at the bottom.

 

Am i on the right course or not?

Link to comment
Share on other sites

nice one, wasn't sure if i was able to refer to active =='0' saying it was from the query

  $q = "select password,active from users where username = '$username'";

Thought i might have to somehow put it into another variable. Altho in saying that it doesn't seem to be working the way I tried.

Link to comment
Share on other sites

A query to confirm a login would be more secure if it was similar to

 

<?php
session_start();

$password = $_POST['password'];
$password = mysql_real_escape_string($password);
$password = htmlentities($password);
$password = htmlspecialchars($password);
$password = MD5($password);

$username = $_POST['username'];
$username = mysql_real_escape_string($username);
$username = htmlentities($username);
$username = htmlspecialchars($username);

$sql = sprintf( "SELECT * FROM `users` WHERE `username` = '%s' AND `password` = '%s' LIMIT 1", $username, $password );
$sql = mysql_query( $sql ) or die( 'Error: ' . mysql_error() );
$obj = mysql_fetch_object( $sql );

if ( $obj ) {
  $_SESSION['logged'] = true;
  echo 'Logged in successfully';
} else {
  $_SESSION['logged'] = false;
  echo 'Invalid details';
}
?>

 

But the answer to your question is yes, you are on the right track.[

Link to comment
Share on other sites

Thanks for all your help, that worked well 'The Little Guy'. Am still trying to learn PHP and am doing a website involving a lot of it for university so your help is much appreciated. Still don't know much about the security aspect of it all but would like to look into it more when i get time but think i'll be starting on getting php mailer set up and email registration and activation next.

 

Is the code i am using very unsecure Wolphie?

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.