JTapp Posted February 26, 2008 Share Posted February 26, 2008 It's quite possible that this is impossible.. but here goes... I have some personnel data that is being reported in a table and in that table I have a field that holds a person's "title". Let's say the returned "title" results are "President", "Vice President", "Assistant To The President" and "Assistant to the Vice President". There are not more than four of them. Does anybody have any idea if I could sort the returned results based on the above heirarchy - which is not alphabetical? Here is my code: echo "<center>\n"; echo "<H2>Roster</H2>\n"; echo "<table border='1'> <tr> <th>Title</th> <th>First Name</th> <th>Last Name</th> </tr>"; if (mysql_num_rows($query)) { while ($row = mysql_fetch_array($query)) { $variable1=$row["title"]; $variable2=$row["firstname"]; $variable3=$row["lastname"]; //table layout print("<tr>"); echo "<tr align=\"center\" bgcolor=\"#EFEFEF\">\n"; echo "<td class=\"td_id\">$variable1</td>\n"; echo "<td class=\"td_id\">$variable2</td>\n"; echo "<td class=\"td_id\">$variable3</td>\n"; print("</tr>"); Thanks for looking at it! Quote Link to comment Share on other sites More sharing options...
unsider Posted February 26, 2008 Share Posted February 26, 2008 Couldn't that potientally done in CSS? Maybe I'm misunderstanding your question, but I am not qualified enough to help you, but if you're doing some research look from something with CSS. Quote Link to comment Share on other sites More sharing options...
PFMaBiSmAd Posted February 26, 2008 Share Posted February 26, 2008 Using a mysql CASE statement to assign a value for the different titles, then doing an ORDER BY that value will allow an arbitrary sort order. See this link for an example - http://www.shawnolson.net/a/722/mysql-arbitrary-ordering.html Quote Link to comment Share on other sites More sharing options...
JTapp Posted February 26, 2008 Author Share Posted February 26, 2008 I spent the last hour researching the suggestions you guys have made, but I'm not any closer to finding a solution. Can you offer more details? I'm really quite the beginner at this... Quote Link to comment Share on other sites More sharing options...
DarkerAngel Posted February 26, 2008 Share Posted February 26, 2008 Try this, it's kind of redundant but should work in your situation: But this will only output for rows those 4 fields: <?php if (mysql_num_rows($query)) { ranksort("President"); ranksort("Vice President"); ranksort("Assistant To The President"); ranksort("Assistant to the Vice President"); } function ranksort($level) { while ($row = mysql_fetch_array($query)) { if($row['title'] == $level) { $variable1=$row["title"]; $variable2=$row["firstname"]; $variable3=$row["lastname"]; //table layout print("<tr>"); echo "<tr align=\"center\" bgcolor=\"#EFEFEF\">\n"; echo "<td class=\"td_id\">$variable1</td>\n"; echo "<td class=\"td_id\">$variable2</td>\n"; echo "<td class=\"td_id\">$variable3</td>\n"; print("</tr>"); } } return true; }?> Quote Link to comment Share on other sites More sharing options...
JTapp Posted February 26, 2008 Author Share Posted February 26, 2008 DarkerAngel - I tried to plug it into my existing code but I got an error message.. here is the entire code with the query.. maybe it makes a difference to your suggestion? <?php //query details table begins $query = mysql_query("SELECT tblLodges.strLodgeName, tblLodges.intLodgeNumber, tblLodges.strDistrictName, tblLodges.strLodgeMailingCity, tblLodges.strLodgeMailingPostCode, tblLodges.strLodgeCounty, tblOfficers.lngLodgeID, tblOfficers.Title, tblOfficers.strFirstName, tblOfficers.strLastName, tblOfficers.BusinessPhone, tblOfficers.PersEmail FROM tblLodges LEFT JOIN tblOfficers ON tblLodges.lngLodgeID = tblOfficers.lngLodgeID WHERE tblLodges.intLodgeNumber=$id LIMIT 0, 50")or die(mysql_error()); echo "<center>\n"; echo "<H2>Roster</H2>\n"; echo "<table border='1'> <tr> <th>Office Number</th> <th>Title</th> <th>First</th> <th>Last</th> <th>Email</th> <th>Phone</th> </tr>"; if (mysql_num_rows($query)) { while ($row = mysql_fetch_array($query)) { $variable1=$row["intLodgeNumber"]; $variable2=$row["Title"]; $variable3=$row["strFirstName"]; $variable4=$row["strLastName"]; $variable5=$row["PersEmail"]; $variable6=$row["BusinessPhone"]; //table layout for results print("<tr>"); echo "<tr align=\"center\" bgcolor=\"#EFEFEF\">\n"; echo "<td class=\"td_id\">$variable1</td>\n"; echo "<td class=\"td_id\">$variable2</td>\n"; echo "<td class=\"td_id\">$variable3</td>\n"; echo "<td class=\"td_id\">$variable4</td>\n"; echo "<td class=\"td_id\">$variable5</td>\n"; echo "<td class=\"td_id\">$variable6</td>\n"; print("</tr>"); } } ?> Quote Link to comment Share on other sites More sharing options...
DarkerAngel Posted February 26, 2008 Share Posted February 26, 2008 I know what I did... i'll try to fix it for you... I didn't send the $query to the function thus it wasn't set, my mistake. Quote Link to comment Share on other sites More sharing options...
DarkerAngel Posted February 26, 2008 Share Posted February 26, 2008 See if this works any better (sorry about above) <?php //query details table begins $query = mysql_query("SELECT tblLodges.strLodgeName, tblLodges.intLodgeNumber, tblLodges.strDistrictName, tblLodges.strLodgeMailingCity, tblLodges.strLodgeMailingPostCode, tblLodges.strLodgeCounty, tblOfficers.lngLodgeID, tblOfficers.Title, tblOfficers.strFirstName, tblOfficers.strLastName, tblOfficers.BusinessPhone, tblOfficers.PersEmail FROM tblLodges LEFT JOIN tblOfficers ON tblLodges.lngLodgeID = tblOfficers.lngLodgeID WHERE tblLodges.intLodgeNumber=$id LIMIT 0, 50")or die(mysql_error()); echo "<center>\n"; echo "<H2>Roster</H2>\n"; echo "<table border='1'> <tr> <th>Office Number</th> <th>Title</th> <th>First</th> <th>Last</th> <th>Email</th> <th>Phone</th> </tr>"; if (mysql_num_rows($query)) { ranksort("President", $query); ranksort("Vice President", $query); ranksort("Assistant To The President", $query); ranksort("Assistant to the Vice President", $query); } function ranksort($level, $query) { while ($row = mysql_fetch_array($query)) { $variable1=$row["intLodgeNumber"]; $variable2=$row["Title"]; $variable3=$row["strFirstName"]; $variable4=$row["strLastName"]; $variable5=$row["PersEmail"]; $variable6=$row["BusinessPhone"]; //table layout for results if($variable2 == $level) { print("<tr>"); echo "<tr align=\"center\" bgcolor=\"#EFEFEF\">\n"; echo "<td class=\"td_id\">$variable1</td>\n"; echo "<td class=\"td_id\">$variable2</td>\n"; echo "<td class=\"td_id\">$variable3</td>\n"; echo "<td class=\"td_id\">$variable4</td>\n"; echo "<td class=\"td_id\">$variable5</td>\n"; echo "<td class=\"td_id\">$variable6</td>\n"; print("</tr>"); } } } ?> EDITED CODE Quote Link to comment Share on other sites More sharing options...
JTapp Posted February 26, 2008 Author Share Posted February 26, 2008 Well, its kind of working... I'm getting "President" in the top row. But that's all I'm getting.. the rest of the staff isn't showing up.. but I know they are there... Quote Link to comment Share on other sites More sharing options...
DarkerAngel Posted February 26, 2008 Share Posted February 26, 2008 Well, its kind of working... I'm getting "President" in the top row. But that's all I'm getting.. the rest of the staff isn't showing up.. but I know they are there... Humm... I was afraid that was how it was going to end up working... Quote Link to comment Share on other sites More sharing options...
JTapp Posted February 26, 2008 Author Share Posted February 26, 2008 I'll keep playing with what you have given me so far.. who knows.. maybe it will click... Quote Link to comment Share on other sites More sharing options...
JTapp Posted February 26, 2008 Author Share Posted February 26, 2008 I found this link.. it seems close to what you were trying to do.. but it makes me REALLY have to concentrate and re-read it several times. Can you look at it and tell me if you think it might be a solution? http://www.wellho.net/resources/ex.php4?item=h999/exc.php Quote Link to comment Share on other sites More sharing options...
JTapp Posted February 26, 2008 Author Share Posted February 26, 2008 OK - scratch that last post. I now have a column called "titleID" For every "president" there is a value of 1 For every "VP" there is a value of 2... etc. Now I have to try to figure out how to make the 'title' field return sorted data, based on the hidden 'titleID' field. Does that make sense? Quote Link to comment Share on other sites More sharing options...
DarkerAngel Posted February 26, 2008 Share Posted February 26, 2008 <?php //query details table begins $query = mysql_query("SELECT tblLodges.strLodgeName, tblLodges.intLodgeNumber, tblLodges.strDistrictName, tblLodges.strLodgeMailingCity, tblLodges.strLodgeMailingPostCode, tblLodges.strLodgeCounty, tblOfficers.lngLodgeID, tblOfficers.Title, tblOfficers.strFirstName, tblOfficers.strLastName, tblOfficers.BusinessPhone, tblOfficers.PersEmail FROM tblLodges LEFT JOIN tblOfficers ON tblLodges.lngLodgeID = tblOfficers.lngLodgeID WHERE tblLodges.intLodgeNumber=$id LIMIT 0, 50")or die(mysql_error()); echo "<center>\n"; echo "<H2>Roster</H2>\n"; echo "<table border='1'> <tr> <th>Office Number</th> <th>Title</th> <th>First</th> <th>Last</th> <th>Email</th> <th>Phone</th> </tr>"; if (mysql_num_rows($query)) { while ($row = mysql_fetch_array($query)) { switch($row["Title"]) { case "President": $p .= formattable($row); break; case "Vice President": $vp .= formattable($row); break; case"Assistant To The President": $attp .= formattable($row); break; case"Assistant to the Vice President": $attvp .= formattable($row); break; default: $other .= formattable($row); } } echo($p.$vp.$attp.$attvp.$other); } function formattable($row) { $variable1=$row["intLodgeNumber"]; $variable2=$row["Title"]; $variable3=$row["strFirstName"]; $variable4=$row["strLastName"]; $variable5=$row["PersEmail"]; $variable6=$row["BusinessPhone"]; //table layout for results $html = "<tr>" $html .= "<tr align=\"center\" bgcolor=\"#EFEFEF\">\n"; $html .= "<td class=\"td_id\">$variable1</td>\n"; $html .= "<td class=\"td_id\">$variable2</td>\n"; $html .= "<td class=\"td_id\">$variable3</td>\n"; $html .= "<td class=\"td_id\">$variable4</td>\n"; $html .= "<td class=\"td_id\">$variable5</td>\n"; $html .= "<td class=\"td_id\">$variable6</td>\n"; $html .= "</tr>" return $html; } ?> I dunno if that don't work I might give up Quote Link to comment Share on other sites More sharing options...
JTapp Posted February 26, 2008 Author Share Posted February 26, 2008 SOLVED. Gosh.. sorry you wrote all that new code. I added a "Group BY" and the Title ID field and we're good to go. Thank you sooo much. My head hurts- I don't know how you Gurus do it! Quote Link to comment Share on other sites More sharing options...
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