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output printing oout in corner!


synchro_irl

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hey guys

i have a big problem withone of all my text, everything is printing out in the bottom left hand corner as can be seen from the image:

 

screenpl1.th.png

its only the text from the if statements that;s printing out there,

any ideas what this might be.

here is the code:

 

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<!--
Design by Free CSS Templates
http://www.freecsstemplates.org
Released for free under a Creative Commons Attribution 2.5 License

Name       : Pluralism
Description: A two-column, fixed-width template fit for 1024x768 screen resolutions.
Version    : 1.0
Released   : 20071218

-->
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Search4Trade</title>
<meta name="keywords" content="" />
<meta name="description" content="" />
<link href="style.css" rel="stylesheet" type="text/css" media="screen" />
</head>
<body>
<div id="wrapper" style="width: 961px; height: 564px">
<div id="wrapper2">
	<div id="header">
		<div id="logo">
			<h1><font size="6">search4trade.net</font></h1>
		</div>
		<div id="menu">
			<ul style="line-height: 170%; text-align: justify; margin-left: 3em; margin-bottom: 1.5em">
				<li><a href="Search1.html">Search </a></li>
				<li><a href="Login1.php">Login</a></li>
				<li><a href="#">Forum</a></li>
				<li><a href="registration.html">Register</a></li>
				<li><a href="adreview.html">Star Rating</a></li>
				<li><a href="#">Contact</a></li>
			</ul>
		</div>
	</div>
	<div id="page">
		<div id="content" style="width: 766px; height: 205px">
			<div class="post">
				<div class="entry">

<p> </p>
<p style="text-align: center">
 </div>
			</div>
		</div>
	</div>
</div>
</div>
<p style="text-align: center"> </p>
</body>

<?php


//Database Information

$dbhost = "";
$dbname = "";
$dbuser = "";
$dbpass = "";

//Connect to database

mysql_connect( $dbhost, $dbuser, $dbpass) or die("Could not connect: ".mysql_error());
mysql_select_db($dbname) or die(mysql_error());

    
   
$username = $_POST['username'];
$type = $_POST['type'];
$StarRating = $_POST['StarRating'];
$commentbox = $_POST['commentbox'];
$name = $_POST['name'];

if(!$_POST['username']){echo 'You must supply a username! click your back button and try again.';exit();}


$check = mysql_query("SELECT * FROM mytable WHERE username = '".$_POST['username']."'")or die(mysql_error());

//Gives error if user dosen't exist
$check2 = mysql_num_rows($check);
if ($check2 == 0) {
die('That username does not exist in our database.');



}





if(!$_POST['name']){echo 'You must supply an name! click your back button and try again.';exit();}


$check = mysql_query("SELECT * FROM mytable WHERE name = '".$_POST['name']."'")or die(mysql_error());

//Gives error if user dosen't exist
$check2 = mysql_num_rows($check);
if ($check2 == 0) {
die('That tradesman does not exist in our database.');



}


if(!$_POST['type']){echo 'You must supply a type! click your back button and try again.';exit();}
if(!$_POST['StarRating']){echo 'You must supply an StarRating! click your back button and try again.';exit();}
if(!$_POST['commentbox']){echo 'You must supply a comment! click your back button and try again.';exit();}


else

{

// use a query to insert the data into the database.

$query = "INSERT INTO myreviews (username, type,StarRating, commentbox, name)
VALUES('$username', '$type','$StarRating','$commentbox','$name')";

mysql_query($query) or die(mysql_error());
mysql_close();

echo "Thank you for your Contribution!";

}

    



?>


</html>

Link to comment
https://forums.phpfreaks.com/topic/93315-output-printing-oout-in-corner/
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A little tip to avoid things like this in future.

 

First make a static html page with some dummy text where your dynamic text will go.

Then write your php code to extract your info from your db and print.

Copy and paste your php code over your dummy text.

 

This way you know it will be in the right place and you know before you start your php coding if the page will look right.

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