subtract month from given date (mm-yyyy)

[Alkimuz]

probably a noob-question, but i have to ask after 2 hours trying to find out for myself..

 

i know how to subtract a month from the date of today and present it like mm-yyyy:

 

date ("m-Y", mktime (0, 0, 0, date("m") - 1, date("d"), date("Y")))

 

but how to subtract a month from an other date that today??

 

so for example, my input is:

 

$date = 01-2003

 

and i want an output like:

 

$lastmonth = 12-2002

 

how to get there?

 

thanks so mutch for any help!

[obsidian]

Try this:

<?php
$date = '01-2003';
list($m, $y) = explode('-', $date);
echo date('m-Y', mktime(0,0,0,$m - 1,1,$y));
?>

 

I believe this will work, even when the date is January, but you may need to test to be sure.

 

[The Little Guy]

This may work (untested):

 

<?php
$date = strtotime('01-2003');
$lastmonth = strtotime  ('-1 month' ,$date);
echo $lastmonth;
?>

[obsidian]

This may work (untested):

 

<?php
$date = strtotime('01-2003');
$lastmonth = strtotime  ('-1 month' ,$date);
echo $lastmonth;
?>

 

Good thought, but as MM-YYYY is not a valid readable date format, that won't work as is; however, a slight modification will:

<?php
list($m, $y) = explode('-', '02-2003');
echo date('m-Y', strtotime("{$y}-{$m}-01 -1 month"));
?>

[Alkimuz]

You guys Rock!! 

first and third solution work indeed exelent! many thanks, i can continue working now