date format issue, says 1970 always :(

[wmguk]

Hey,

 

I am trying to format a date, its not a timestamp, basically you select the day, month and year from a drop down and its put in to the database in 3 seperate fields..

 

so if i do

$datef = "$date_day"."$date_month"."$date_year" ;

then echo $datef it displays right (17082007)

 

now i try and format the output, and its wrong..

$date = date("jS F Y", $datef);

 

i get 17th February 1970

 

any ideas?

[Jeremysr]

date() wants a UNIX timestamp, which is the number of seconds since January 1, 1970. You can use mktime() to make a UNIX timestamp using the day, month, and year (and minutes, seconds, and hours if you want). This is how you use it:

 

$date = date("jS F Y", mktime(0, 0, 0, $date_month, $date_day, $date_year));

 

The three zeros at the beginning are the hours, minutes, and seconds.

[wmguk]

Ah!! of course!!

 

thank you, I was getting so confused, I knew when I saw 1970 that something was wrong in the formatting, but I just couldnt work it out!

 

Excellent, thank you

[kenrbnsn]

Or you can use the strtotime() function:

<?php
$date = date('jS F Y',strtotime($date_year . '-' . $date_month . '-' $date_day);
?>

 

Ken