bobbyrabbit Posted May 14, 2006 Share Posted May 14, 2006 I'm trying to post to 2 fields in the MySQL Database:I'm generating data from fields DocTitle and DocCost in table 'worktype' in a dropdown box which is working fine. I am trying post this info to another table 'bidrequests' using the same field names on submitting the form. I think the problem is that I'm trying to post more than 1 peice of info via the form. The data to upload is part of an Applet. On clicking the submit button I am getting javascript error Object Required. Here is the code, thanks for any help:document.InterfaceApplet.SETPARAMETER ("DocTitle", document.getElementById("WorkType").value); document.InterfaceApplet.SETPARAMETER ("DocCost", document.getElementById("WorkType").value);-------------------------------------------------------------------------------<select name="WorkType" id="select"> <?php $selected = "";do { if (isset($_POST['WorkType']) && $row_rsDocTitle['DocTitle']==$_POST['WorkType']) $selected = "select"; else $selected = "";?> <option value="<?php echo $row_rsDocTitle['DocTitle']?><?php echo $row_rsDocTitle['DocCost']?>" <?php echo $selected; ?>><?php echo $row_rsDocTitle['DocTitle']?> - <?=$CurrencySymbol?><?php echo $row_rsDocTitle['DocCost']?></option> <?php} while ($row_rsDocTitle = mysql_fetch_assoc($rsDocTitle)); $rows = mysql_num_rows($rsDocTitle); if($rows > 0) { mysql_data_seek($rsDocTitle, 0); $row_rsDocTitle = mysql_fetch_assoc($rsDocTitle); }?> </select>---------------------------------------------------------- Link to comment Share on other sites More sharing options...
trq Posted May 14, 2006 Share Posted May 14, 2006 If your getting a javascript error then the problem is javascript. The name of this forum is [b]php[/b] help. Link to comment Share on other sites More sharing options...
bobbyrabbit Posted May 14, 2006 Author Share Posted May 14, 2006 Apologies, posted to Javascript section, please close this thread. Link to comment Share on other sites More sharing options...
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