PHP Flip Image

[The14thGOD]

I'm trying to figure out how to make this function work, I'm not as familiar with functions and this function doesn't seem to have anything more to explain it. I found it here:

http://www.php.net/manual/en/ref.image.php#62029

<?php
// This is a correction to the image-flipping function I posted previously.
// The bitwise ands (&) were incorrectly written as logical ands (&&).
// Needless to say, that breaks the function in obnoxious--if amusing--ways.

define("VERTICAL", 1);
define("HORIZONTAL", 2);

function imageflip($image, $mode) {
       $w = imagesx($image);
       $h = imagesy($image);
       $flipped = imagecreate($w, $h);
       if ($mode & VERTICAL) {
               for ($y = 0; $y < $h; $y++) {
                       imagecopy($flipped, $image , 0, $y, 0, $h - $y - 1, $w, 1);
               }
       }
       if ($mode & HORIZONTAL) {
               for ($x = 0; $x < $w; $x++) {
                       imagecopy($flipped, $image , $x, 0, $w - $x - 1, 0, 1, $h);
               }
       }
       return $flipped;
}
?>

I've called the function before and put the image location into where image is but I'm confused on the mode.

Anyone familiar with this?

Any help would be great, thanks in advance.

 

Justin

[Barand]

Different MODE results

[pre]

                          O                                            O

                          \                                          / 

    original              \                      HORIZONTAL        / 

                            X                                      X   

                               

                            X 

    VERTICAL              / 

                          /   

                          O   

 

[The14thGOD]

What?

I don't understand how I choose vert/horizontal...it says if mode & vert then do this, but...the only 2 arguments are image and mode...

[Barand]

$flipped = flip_image ($image, VERTICAL);

[The14thGOD]

Alright, that clears up some of it, like I said I'm new to functions and I appreciate the help.

 

I've run into a problem displaying the image, here's some examples of what I've tried

 

<?php include("includes/flip_image.php"); 
			$image = "images/sideimgs/side02.jpg";
			imageflip("images/sideimgs/side02.jpg",HORIZONTAL);
//imageflip($image,HORIZONTAL);
		?>
		<img class="rightimg" src="<?= $flipped ?>" width="154" height="768" alt="Side Image" />

 

I've also tried putting 1 line into where the $flipped is, so $flipped = imageflip($image,HORIZONTAL).

 

Nothing shows up in the code when i look at the source, it looks like src="".

Again, ty for the help.

[Barand]

$image needs to be a GD image, not a filename.