Checking for word length...

[phpnoobie9]

Is this correct...it seems like I just keep getting my else statement when I insert in words into a form.

$longtext should check for words that are longer that 20 characters without any space from the description which is the textarea of the form.

 

 

$description is the textarea name on the form.

$longtext = preg_match('/^\S{20,}$/', $description);
if($description != $longtext) {
if word is not longer than 20 characters do this
else {
if a word has more than 20 characters without any blank space do this
}

[BlueSkyIS]

i'd just use strlen()

 

if(strlen(str_replace(" ","",$description)) <= 20) {
    //if word is not longer than 20 characters do this
else {
    //if a word has more than 20 characters without any blank space do this
}

[MasterACE14]

i'd just use strlen()

 

and use str_replace() for the spaces.

 

EDIT: beat me to it

[BlueSkyIS]

haha, thought of it after i posted and updated my post. 

[phpnoobie9]

i'd just use strlen()

 

So if I use strlen($description) won't that count every character in $description including space? My goal is to not let the form submit if a there was a word found that has more than 20 characters without a space.

 

i'd just use strlen()

 

and use str_replace() for the spaces.

 

EDIT: beat me to it

 

I don't want to replace the word.. I want to echo the else which will say something along the lines of error.

[MasterACE14]

I think I get what you mean... maybe you should be breaking the word up into a array?

[phpnoobie9]

So..how do I count the each word?

[BlueSkyIS]

you're not replacing anything except removing the spaces before measuring what's left over.

 

$description = "this is a bit of text";

if(strlen(str_replace(" ","",$description)) <= 20) {
   //if word is not longer than 20 characters do this
else {
   //if a word has more than 20 characters without any blank space do this
}

echo $description;

 

output:

this is a bit of text

 

[phpnoobie9]

you're not replacing anything except removing the spaces before measuring what's left over.

 

$description = "this is a bit of text";

if(strlen(str_replace(" ","",$description)) <= 20) {
   //if word is not longer than 20 characters do this
else {
   //if a word has more than 20 characters without any blank space do this
}

echo $description;

 

output:

this is a bit of text

 

 

So " " is equal to space what about ""? Isn't this telling space to replace $description? then...if $description is <= 20 do if..

 

Just need a little explaining so I'll understand the code.

Thanks.

[phpnoobie9]

I did tried the code BlueSkyIs posted, but it's counting everything in the description textarea. So if I have several words with a few characters..that adds up to 10 or more it'll echo else.

[KrisNz]

If I understand the problem correctly (you want to find, in a string, if theres at least one word longer than 20 characters),I think your original regex would work if you took out those anchors (the ^ and the $).

 

<?php
$desc = <<<EOF

This is a test sentence with
a supercalafragalisticexpialedocius
word

EOF;

if (preg_match("/\S{20,}/",$desc)) {
    echo "match";
} else {
    echo "no words longer than 20 chars";
}
?>

[sasa]

try

$longtext = preg_match('/\S{20,}/', $description);
if(!$longtext) {
if word is not longer than 20 characters do this
else {
if a word has more than 20 characters without any blank space do this
}