jdorenbush Posted April 6, 2008 Share Posted April 6, 2008 I was making a few changes to the admin side of a PHP based Bookstore I have. Somewhere along the lines I broke it and I am no PHP expert so I am having a heck of a time fixing it. I am unable to edit or add books to the database now. I keep getting the ERROR message. Here is the "Add Books" portion of the code. Does anyone see something that stands out as incorrect? Code: // Add Books if ( $action == "AddBook" ) { echo " <form action=\"?action=doAddBook\" method=\"POST\"> <fieldset> <legend>Add Book</legend> <label for=\"book_cover\">Book Cover URL</label><input type=\"text\" name=\"book_cover\" class=\"txt\"> <label for=\"book_title\">Title</label><input type=\"text\" name=\"book_title\" class=\"txt\" > <label for=\"book_author\">Author</label><input type=\"text\" name=\"book_author\" class=\"txt\" > <label for=\"book_publisher\">Publisher</label><input type=\"text\" name=\"book_publisher\" class=\"txt\" > <label for=\"book_publication\">Publication Year</label><input type=\"text\" name=\"book_publication\" class=\"txt\" > <label for=\"book_isbn\">ISBN</label><input type=\"text\" name=\"book_isbn\" class=\"txt\" > <label for=\"book_covertype\">Book Cover Type</label><select name=\"book_covertype\" class=\"txt\" > <option selected> </option> <option value=\"Hard\">Hard Cover</option> <option value=\"Soft\">Soft Cover</option> </select> <label for=\"book_pages\">Pages</label><input type=\"text\" name=\"book_pages\" class=\"txt\" > <label for=\"book_condition\">Condition</label><select name=\"book_condition\" class=\"txt\" ><option selected> </option> <option value=\"New\">New</option> <option value=\"Used/Like New\">Used/Like New</option> <option value=\"Used/Slight Wear\">Used/Slight Wear</option> <option value=\"Used/Worn\">Used/Worn</option> </select> <label for=\"book_category\">Category</label><select name=\"book_category\" class=\"txt\" > <option selected> </option>"; $query = " SELECT * FROM categories ORDER BY cat_id ASC"; $result = mysql_query($query) or die('Error, query failed'); while ($getcat= mysql_fetch_array($result)) { echo "<option value=\"$getcat[cat_name]\">$getcat[cat_name]</option>";} echo " </select><br /><br /> <label for=\"book_listprice\">List Price</label><input type=\"text\" name=\"book_listprice\" class=\"txt\" value=\"$\" > <label for=\"book_amazonprice\">Amazon Price</label><input type=\"text\" name=\"book_amazonprice\" class=\"txt\" value=\"$\" > <label for=\"book_price\">Mutineer Price</label><input type=\"text\" name=\"book_price\" class=\"txt\" value=\"$\" > <label for=\"book_summary\">Book Summary</label><textarea name=\"book_summary\" cols=\"30\" rows=\"3\" class=\"txt\"></textarea> <label for=\"book_whothis\">Who its For</label><textarea name=\"book_whothis\" cols=\"30\" rows=\"3\" class=\"txt\"></textarea> <label for=\"book_opinion\">Mutineer's Opinion</label><textarea name=\"book_opinion\" cols=\"30\" rows=\"3\" class=\"txt\"></textarea> <label for=\"book_approved\">Mutineer Approved?</label><br /><br /> Yes<input name=\"book_approved\" type=\"radio\" value=\"Yes\" /> No<input name=\"book_approved\" type=\"radio\" value=\"No\" /><br /><br /> <label for=\"book_essential\">Mutineer Essential?</label><br /><br /> Yes<input name=\"book_essential\" type=\"radio\" value=\"Yes\" /> No<input name=\"book_essential\" type=\"radio\" value=\"No\" /><br /><br /> <p><input type=\"Submit\" value=\"Submit\" class=\"txt2\"></p> </fieldset> </form> ";} if ( $action == "doAddBook" ) { $book_cover=mysql_real_escape_string($_POST['book_cover']); $book_title=mysql_real_escape_string($_POST['book_title']); $book_author=mysql_real_escape_string($_POST['book_author']); $book_publisher=mysql_real_escape_string($_POST['book_publisher']); $book_publication=mysql_real_escape_string($_POST['book_publication']); $book_isbn=mysql_real_escape_string($_POST['book_isbn']); $book_covertype=mysql_real_escape_string($_POST['book_covertype']); $book_pages=mysql_real_escape_string($_POST['book_pages']); $book_condition=mysql_real_escape_string($_POST['book_condition']); $book_listprice=mysql_real_escape_string($_POST['book_listprice']); $book_amazonprice=mysql_real_escape_string($_POST['book_amazonprice']); $book_price=mysql_real_escape_string($_POST['book_price']); $book_summary=mysql_real_escape_string($_POST['book_summary']); $book_whothis=mysql_real_escape_string($_POST['book_whothis']); $book_opinion=mysql_real_escape_string($_POST['book_opinion']); $book_approved=mysql_real_escape_string($_POST['book_approved']); $book_essential=mysql_real_escape_string($_POST['book_essential']); $query = " INSERT INTO catalog VALUES('','$book_cover','$book_title','$book_author','$book_publisher','$book_publication','$book_isbn','$book_covertype','$book_pages','$book_condition','$book_listprice','$book_amazonprice','$book_price','$book_summary','$book_whothis','$book_opinion','$book_approved','$book_essential')"; $result = mysql_query($query) or die('ERROR: Unable to add book.'); echo "<h2>The book has been successfully added to the database.</h2>"; } MySQL: 4.1.20-3 / PHP: 4.3.9 Hosting: RackForce Here is a screenshot from PHPMyAdmin: Any help is much appreciated... Remember, take it easy on me - I am a PHP noob. Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 6, 2008 Share Posted April 6, 2008 What error are you getting? Ken Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 6, 2008 Author Share Posted April 6, 2008 What error are you getting? Ken After pressing submit it brings me to a page and says "Unable to add book." $result = mysql_query($query) or die('ERROR: Unable to add book.'); Quote Link to comment Share on other sites More sharing options...
tippy_102 Posted April 6, 2008 Share Posted April 6, 2008 Unless I'm overlooking something, you haven't told INSERT which columns to insert into. Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 6, 2008 Share Posted April 6, 2008 You can leave out the columns if you supply all the values. Change <?php $result = mysql_query($query) or die('ERROR: Unable to add book.'); ?> to <?php $result = mysql_query($query) or die("ERROR: Unable to add book. The query was: $query<br>" . mysql_error()); ?> This will show you the query and the mysql_error that caused the problem. Post the results. Ken Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 6, 2008 Author Share Posted April 6, 2008 You can leave out the columns if you supply all the values. Change <?php $result = mysql_query($query) or die('ERROR: Unable to add book.'); ?> to <?php $result = mysql_query($query) or die("ERROR: Unable to add book. The query was: $query<br>" . mysql_error()); ?> This will show you the query and the mysql_error that caused the problem. Post the results. Ken ERROR: Unable to update book. The query was: UPDATE catalog SET book_cover='bartendingfordummies.jpg',book_title='Bartending for Dummies', book_author='Ray Foley', book_publisher='IDG Books', book_publication='1997', book_isbn='0-7645-5051-9', book_covertype='', book_pages='', book_condition='', book_listprice='', book_amazonprice='', book_price='$9.99', book_summary='A basic guide to everything bartending and mixology.', book_whothis='Anyone interested in bartending or mixology; good starter book.', book_summary='A basic guide to everything bartending and mixology.', book_opinion='I’m typically not a fan of books in the “Dummies” series…not sure why, just not for some reason. This book, however, has been a useful tool for me over the years. If nothing else, it contains an accurate density chart for layering liquors and liqueurs. The book is laid out in an approachable and sensible way, and does a good job covering the basics of bartending, mixology, and spirits.', book_approved='', book_essential='', WHERE book_id='' You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'WHERE book_id=''' at line 1 Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 6, 2008 Share Posted April 6, 2008 All of a sudden you're showing an error with an Update, which is not in the code you showed. Anyway, the problem here is that you have a comma before the "Where" clause which is incorrect. Also, the book_id is null, so if the update were to work, it wouldn't update the correct record. Ken Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 6, 2008 Author Share Posted April 6, 2008 Whoops. That was the EDIT(UPDATE) portion. Here is what happens when I try and ADD. ERROR: Unable to add book. The query was: INSERT INTO catalog VALUES('','test','test','test','test','test','test','Hard','test','New','$test','$test','$test','test','test','test','Yes','Yes') Column count doesn't match value count at row 1 I fixed the comma in the EDIT portion, but how do I address the null ID? Quote Link to comment Share on other sites More sharing options...
maxudaskin Posted April 6, 2008 Share Posted April 6, 2008 You need to put all the columns in first... Eg: INSERT INTO table (column1,column2,column3) VALUES ('$testvar','test','test') Quote Link to comment Share on other sites More sharing options...
maxudaskin Posted April 6, 2008 Share Posted April 6, 2008 Try <?php mysql_query("INSERT INTO catalog (`column1``column2`,`column3`,`column4`,`column5`,`column6,`column7`,`column8,`column9`,`column10`,`column11`,`column12`,`column13`,`column14`,`column15`,`column16`,`column17`,`column17`)VALUES('','test','test','test','test','test','test','Hard','test','New','$test','$test','$test','test','test','test','Yes','Yes')") ?> But replace column1 or whatever with the column name. Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 6, 2008 Share Posted April 6, 2008 As I said before, you do not have to include the column names [red]if[/red] you have values for all the columns listed. In this case, the error is telling you that you don't. I fixed the comma in the EDIT portion, but how do I address the null ID? For us to tell you that, we need to see the code for the update portion. Ken Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 7, 2008 Author Share Posted April 7, 2008 I fixed the comma in the EDIT portion, but how do I address the null ID? For us to tell you that, we need to see the code for the update portion. Ken if ( $action == "EditBook" ) { $id=$_GET['id']; $query = "SELECT * FROM catalog WHERE book_id = '$id'"; $result = mysql_query($query) or die('Couldnt read book catalog database'); $book_cover=mysql_result($result,$i,"book_cover"); $book_title=mysql_result($result,$i,"book_title"); $book_author=mysql_result($result,$i,"book_author"); $book_publisher=mysql_result($result,$i,"book_publisher"); $book_publication=mysql_result($result,$i,"book_publication"); $book_isbn=mysql_result($result,$i,"book_isbn"); $book_covertype=mysql_result($result,$i,"book_covertype"); $book_pages=mysql_result($result,$i,"book_pages"); $book_condition=mysql_result($result,$i,"book_condition"); $book_listprice=mysql_result($result,$i,"book_listprice"); $book_amazonprice=mysql_result($result,$i,"book_amazonprice"); $book_price=mysql_result($result,$i,"book_price"); $book_summary=mysql_result($result,$i,"book_summary"); $book_whothis=mysql_result($result,$i,"book_whothis"); $book_opinion=mysql_result($result,$i,"book_opinion"); $book_approved=mysql_result($result,$i,"book_approved"); $book_essential=mysql_result($result,$i,"book_essential"); echo " <form action=\"?action=doEditBook\" method=\"POST\"> <fieldset> <legend>Edit Book with ID $id</legend> <input type=\"hidden\" name=\"id\" value=\"$id\"> <label for=\"book_cover\">Book Cover URL</label><input type=\"text\" name=\"book_cover\" class=\"txt\" value=\"$book_cover\" > <label for=\"book_title\">Title</label><input type=\"text\" name=\"book_title\" class=\"txt\" value=\"$book_title\" > <label for=\"book_author\">Author</label><input type=\"text\" name=\"book_author\" class=\"txt\" value=\"$book_author\" > <label for=\"book_publisher\">Publisher</label><input type=\"text\" name=\"book_publisher\" class=\"txt\" value=\"$book_publisher\" > <label for=\"book_publication\">Publication Year</label><input type=\"text\" name=\"book_publication\" class=\"txt\" value=\"$book_publication\" > <label for=\"book_isbn\">ISBN</label><input type=\"text\" name=\"book_isbn\" class=\"txt\" value=\"$book_isbn\" > <label for=\"book_covertype\">Book Cover Type</label><select name='book_covertype' class=\"txt\"value=\"$book_covertype\" ><option selected value=\"$book_covertype\"></option> <option value=\"Hard\">Hard Cover</option> <option value=\"Soft\">Soft Cover</option> </select> <label for=\"book_pages\">Pages</label><input type=\"text\" name=\"book_pages\" class=\"txt\" value=\"$book_pages\" > <label for=\"book_condition\">Condition</label><select name='book_condition' class=\"txt\" ><option selected value=\"$book_condition\"></option> <option value=\"New\">New</option> <option value=\"Used/Like New\">Used/Like New</option> <option value=\"Used/Slight Wear\">Used/Slight Wear</option> <option value=\"Used/Worn\">Used/Worn</option> </select> <label for=\"book_category\">Category</label><select name='book_category' class=\"txt\"><option selected value=\"$book_category\"> </option>"; $query = " SELECT cat_name FROM categories"; $result = mysql_query($query) or die('Cant select categories table'); while ($getcat= mysql_fetch_array($result)) { ?> <? echo "<option value=\"$getcat[cat_name]\""; ?> <? if ($getcat[cat_name]=="$book_category"){ echo " selected>"; } else { echo ">"; } ?> <? echo "$getcat[cat_name]</option>"; ?><? } echo " </select><br /><br /> <label for=\"book_listprice\">List Price</label><input type=\"text\" name=\"book_listprice\" class=\"txt\" value=\"$book_listprice\" > <label for=\"book_amazonprice\">Amazon Price</label><input type=\"text\" name=\"book_amazonprice\" class=\"txt\" value=\"$book_amazonprice\" > <label for=\"book_price\">Mutineer Price</label><input type=\"text\" name=\"book_price\" class=\"txt\" value=\"$book_price\" > <label for=\"book_summary\">Book Summary</label><textarea name='book_summary' cols='30' rows='3' class=\"txt\">$book_summary</textarea> <label for=\"book_whothis\">Who its For</label><textarea name='book_whothis' cols='30' rows='3' class=\"txt\">$book_whothis</textarea> <label for=\"book_opinion\">Mutineer's Opinion</label><textarea name='book_opinion' cols='30' rows='3' class=\"txt\">$book_opinion</textarea> <label for=\"book_approved\"><font color=\"red\">Mutineer Approved?</font></label><br /><br /> Yes<input name=\"book_approved\" type=\"radio\" value=\"Yes\" /> No<input name=\"book_approved\" type=\"radio\" value=\"No\" /><br /><br /> <label for=\"book_essential\"><font color=\"red\">Mutineer Essential<?/font></label><br /><br /> Yes<input name=\"book_essential\" type=\"radio\" value=\"Yes\" /> No<input name=\"book_essential\" type=\"radio\" value=\"No\" /><br /><br /> <p><input type=\"Submit\" value=\"Submit\" class=\"txt2\"></p> </fieldset> </form>"; } if ( $action == "doEditBook" ) { $book_cover=mysql_real_escape_string($_POST['book_cover']); $book_title=mysql_real_escape_string($_POST['book_title']); $book_author=mysql_real_escape_string($_POST['book_author']); $book_publisher=mysql_real_escape_string($_POST['book_publisher']); $book_publication=mysql_real_escape_string($_POST['book_publication']); $book_isbn=mysql_real_escape_string($_POST['book_isbn']); $book_covertype=mysql_real_escape_string($_POST['book_covertype']); $book_pages=mysql_real_escape_string($_POST['book_pages']); $book_condition=mysql_real_escape_string($_POST['book_condition']); $book_listprice=mysql_real_escape_string($_POST['book_listprice']); $book_amazonprice=mysql_real_escape_string($_POST['book_amazonprice']); $book_price=mysql_real_escape_string($_POST['book_price']); $book_summary=mysql_real_escape_string($_POST['book_summary']); $book_whothis=mysql_real_escape_string($_POST['book_whothis']); $book_opinion=mysql_real_escape_string($_POST['book_opinion']); $book_approved=mysql_real_escape_string($_POST['book_approved']); $book_essential=mysql_real_escape_string($_POST['book_essential']); $query = "UPDATE catalog SET book_cover='$book_cover',book_title='$book_title', book_author='$book_author', book_publisher='$book_publisher', book_publication='$book_publication', book_isbn='$book_isbn', book_covertype='$book_covertype', book_pages='$book_pages', book_condition='$book_condition', book_listprice='$book_listprice', book_amazonprice='$book_amazonprice', book_price='$book_price', book_summary='$book_summary', book_whothis='$book_whothis', book_summary='$book_summary', book_opinion='$book_opinion', book_approved='$book_approved', book_essential='$book_essential' WHERE book_id='$id'"; $result = mysql_query($query) or die("ERROR: Unable to update book. The query was: $query<br>" . mysql_error()); echo "<h2>The book has been successfully updated in the database.</h2>"; } Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 7, 2008 Author Share Posted April 7, 2008 UPDATE: I've sort of fixed the EDIT portion of the admin. It was looking for ID when it should have been looking for BOOK_ID. So it UPDATES the record, but when I go back to view whats its supposedly updated, it shows me nothing that I edited. Now I need to fix the ADD portion. It looks like the field I am missing is the BOOK_ID when I am trying to add a book. The ID is just supposed to auto-increment for each book I add. Where/what would I include so that it inserts an auto-incremented book ID # into the database for each book I add? Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 8, 2008 Author Share Posted April 8, 2008 *bump* Almost fixed guys just need a bit more help fixing the whats listed above. Thanks! Quote Link to comment Share on other sites More sharing options...
conker87 Posted April 8, 2008 Share Posted April 8, 2008 Try: <?php if ( $action == "doEditBook" ) { $book_cover=mysql_real_escape_string($_POST['book_cover']); $book_title=mysql_real_escape_string($_POST['book_title']); $book_author=mysql_real_escape_string($_POST['book_author']); $book_publisher=mysql_real_escape_string($_POST['book_publisher']); $book_publication=mysql_real_escape_string($_POST['book_publication']); $book_isbn=mysql_real_escape_string($_POST['book_isbn']); $book_covertype=mysql_real_escape_string($_POST['book_covertype']); $book_pages=mysql_real_escape_string($_POST['book_pages']); $book_condition=mysql_real_escape_string($_POST['book_condition']); $book_listprice=mysql_real_escape_string($_POST['book_listprice']); $book_amazonprice=mysql_real_escape_string($_POST['book_amazonprice']); $book_price=mysql_real_escape_string($_POST['book_price']); $book_summary=mysql_real_escape_string($_POST['book_summary']); $book_whothis=mysql_real_escape_string($_POST['book_whothis']); $book_opinion=mysql_real_escape_string($_POST['book_opinion']); $book_approved=mysql_real_escape_string($_POST['book_approved']); $book_essential=mysql_real_escape_string($_POST['book_essential']); $book_id=mysql_real_escape_string($_POST['id']); // Added this, since you've put your id in a hidden field, it needs a variable assigned to it (since using $_POST['id'] can get complicated) $query = "UPDATE catalog SET book_cover='$book_cover',book_title='$book_title', book_author='$book_author', book_publisher='$book_publisher', book_publication='$book_publication', book_isbn='$book_isbn', book_covertype='$book_covertype', book_pages='$book_pages', book_condition='$book_condition', book_listprice='$book_listprice', book_amazonprice='$book_amazonprice', book_price='$book_price', book_summary='$book_summary', book_whothis='$book_whothis', book_summary='$book_summary', book_opinion='$book_opinion', book_approved='$book_approved', book_essential='$book_essential' WHERE book_id='$book_id'"; $result = mysql_query($query) or die("ERROR: Unable to update book. The query was: $query<br>" . mysql_error()); echo "<h2>The book has been successfully updated in the database.</h2>"; } ?> Quote Link to comment Share on other sites More sharing options...
Barand Posted April 8, 2008 Share Posted April 8, 2008 Now I need to fix the ADD portion. It looks like the field I am missing is the BOOK_ID when I am trying to add a book. The ID is just supposed to auto-increment for each book I add. Where/what would I include so that it inserts an auto-incremented book ID # into the database for each book I add? Suppose your book records are book_id | book_cover | book_title | book_author you can either supply all column names except "book_id" INSERT INTO book (book_cover, book_title, book_author) VALUES ('x', 'y', 'z') or use a null value for the auto_inc id so all values are still provided in the correct order INSERT INTO book VALUES (null, 'x', 'y', 'z') edit: P.S. or you can do both, of course INSERT INTO book (book_id, book_cover, book_title, book_author) VALUES (null, 'x', 'y', 'z') Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 8, 2008 Share Posted April 8, 2008 Since you've named your form fields the same as the database fields you can let PHP do the work of creating the correct query: <?php if ($action == 'doEditBook') { $qtmp = array(); foreach ($_POST as $k => $v) if ($k != 'submit' && $k != 'id') $qtmp[] = $k . " = '" . mysql_real_escape_string(trim(stripslashes($v))) . "'"; $query = "UPDATE catalog SET " . implode(', ',$qtmp) . " WHERE book_id='" . mysql_real_escape_string($_POST['id']) . "'"; $result = mysql_query($query) or die("ERROR: Unable to update book. The query was: $query<br>" . mysql_error()); echo "<h2>The book has been successfully updated in the database.</h2>"; } ?> Ken Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 8, 2008 Author Share Posted April 8, 2008 Since you've named your form fields the same as the database fields you can let PHP do the work of creating the correct query: <?php if ($action == 'doEditBook') { $qtmp = array(); foreach ($_POST as $k => $v) if ($k != 'submit' && $k != 'id') $qtmp[] = $k . " = '" . mysql_real_escape_string(trim(stripslashes($v))) . "'"; $query = "UPDATE catalog SET " . implode(', ',$qtmp) . " WHERE book_id='" . mysql_real_escape_string($_POST['id']) . "'"; $result = mysql_query($query) or die("ERROR: Unable to update book. The query was: $query<br>" . mysql_error()); echo "<h2>The book has been successfully updated in the database.</h2>"; } ?> Ken Hey it worked! Very compact code to. It looks great, I don't fully understand it, but in time I will make sense of it. Is it possible to use something along those lines for doAddBook? Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 8, 2008 Share Posted April 8, 2008 Yes, just change the "update" to "insert" and remove the "where" clause. This format is the alternative "insert" format, which most people don't use. Ken Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 9, 2008 Author Share Posted April 9, 2008 This is what I came up with... if ($action == 'doAddBook') { $qtmp = array(); foreach ($_POST as $k => $v) if ($k != 'submit' && $k != 'id') $qtmp[] = $k . " = '" . mysql_real_escape_string(trim(stripslashes($v))) . "'"; $query = "INSERT catalog SET " . implode(', ',$qtmp) . mysql_real_escape_string($_POST['id']) . "'"; $result = mysql_query($query) or die("ERROR: Unable to add book. The query was: $query<br />" . mysql_error()); echo "<h2>The book has been successfully added to the database.</h2>"; } I received an error though... You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''''' at line 1 I don't really understand this script so its really difficult for me to try and solve the problem. Quote Link to comment Share on other sites More sharing options...
kenrbnsn Posted April 9, 2008 Share Posted April 9, 2008 You're not creating the correct query. Try: <?php if ($action == 'doAddBook') { $qtmp = array(); foreach ($_POST as $k => $v) if ($k != 'submit') $qtmp[] = $k . " = '" . mysql_real_escape_string(trim(stripslashes($v))) . "'"; $query = "INSERT catalog SET " . implode(', ',$qtmp); $result = mysql_query($query) or die("ERROR: Unable to add book. The query was: $query<br />" . mysql_error()); echo "<h2>The book has been successfully added to the database.</h2>"; }?> Ken Quote Link to comment Share on other sites More sharing options...
jdorenbush Posted April 9, 2008 Author Share Posted April 9, 2008 Works great! Thanks Ken! Quote Link to comment Share on other sites More sharing options...
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