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Showing content with the highest reputation on 07/30/2022 in all areas

  1. the error is because you are using three different names for the same thing and you don't seem to be able to keep track of which name you are using. if the column in the database table is named customer_id, i recommend that you use that same name for that value throughout the code, e.g. for the get parameter name (user_id), one unnecessarily copied php variable name (id), another unnecessarily copied php variable name (customer_id), and the prepared query place-holder name (id). consistency and simplicity counts in programming, so you are not wasting time trying to keep track of three different names for the same thing.
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