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fugix

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Posts posted by fugix

    PHP script for AJAX

    in PHP Coding Help

    Posted

    Wow!!!

    Thanks for al the quick replies!!!

    Here is my AJAX code:

    <html>
<head>
<script type="text/javascript">
function showHint(str)
{
var xmlhttp;
if (str.length==0)
  { 
  document.getElementById("txtHint").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","ajax_test.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>

<h3>Start typing a name in the input field below:</h3>
<form action=""> 
First name: <input type="text" id="txt1" onkeyup="showHint(this.value)" />
</form>
<p>Suggestions: <span id="txtHint"></span></p> 

</body>
</html>

     

    Btw to make it easier to understand for you all Voornaam means firstname in dutch.

    I'm going to use this query so people can fill in the first part of a name of a user and it gives some options.

    did Zanus modification not work for you?

    db driven catalog

    in PHP Coding Help

    Posted

    depending on how many rows you wish to grab at a time, to populate a table with values from your db..you will need to use a while loop to cycle through your db values if you plan on grabbing multiple models at a time.. if you simply want to grab the field values for a single row, you will need to use something like 

    $row = mysql_fetch_assoc($query);

    $query being your mysql_query() resource.

    then you can create a table and populate it with the db values that you wish...eg

    <table><tr><td>Gain</td><td><?php echo $row['gain']; ?></td></tr>

    etc...now if you are wanting to grab multiple rows, you will need the while loop i stated above..

    while ($row = mysql_fetch_assoc($query)) {

  echo "<table><tr><td>Gain</td><td>{$row['gain']}</td></tr>";
}

    hope this helps

    Javascript not work at all

    in Javascript Help

    Posted

    If he'd asked.. "what's the logically inept way of making this work?" - then yeah, you answered his call.

    and if he asked...hey i want to know the logic behind what im doing even though I am in a hurry in school and I really dont care or have 2 hours to talk to someone about the logic instead of getting the answer that I want...you did a good job.

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