[Passing value by post to a new php file]

whatever php file you want to send the data to...make that php file your action in your form

<form method='post' action='example.php' >

 

[PHP GET Request and responce...please help!!]

yes that was my mistake...im looking into it now.

[multiple strings being value of one string]

are you setting your $year $month $day vars to $_POST vars?

[multiple strings being value of one string]

$shutoff = $year . "-" . $month . "-" . $day;

 

should be what you are looking for

[Want a PHP code to display Popup message when a image is clicked on!]

you would have to rely on javascript's "alert" function.

[PHP GET Request and responce...please help!!]

try what I have suggested and let me know what you receive

[PHP GET Request and responce...please help!!]

this is because the return type of this

echo $r->getResponseBody() ;

 

is a string...

 

try

 

echo $r->getBodyDocument() ;

[if statement depending on the value returned from the database]

this line

Echo "<a href='viewprofile.php?username={$info['username']}'><img src='http://datenight.netne.net/images/".$info['img'] ."' width='30' height='30''></a>".$info['from_user']." ".$info['message'];

 

should be

echo "<a href='viewprofile.php?username={$info['username']}'><img src='http://datenight.netne.net/images/".$info['img'] ."' width='30' height='30''></a>".$info['from_user']." ".$info['message'] . ";

 

you forgot to end you concatenation on the end

 

[unicode letters]

preg_replace('#[^A-Za-z0-9]#i', $replacement, $str_to_search);

[need OR in SELECT query]

depending on where this is in your query..you may have to close them inside parenthesis

[need OR in SELECT query]

try changing it to

members_count <= ".$diff." or members_count >= ".$defmemcount."

 

["simple" calculation]

AND team_treasure>='members_count * 1000' 

[Update 2 Tables]

i will do a couple so you can understand how to do this..

$sql = "UPDATE companies, iQuestions SET
                                 companies.companyname = '${name}',
                                 companies.companytag = '${tag}',
                                 companies.companywebsite = '${website}',
                                 companies.industry = '${industry}',
                                 companies.stage = '${stage}',
                                 companies.country = '${country}',
                                 companies.state = '${state}',
                                 companies.city = '${city}',
                                 iQuestions.capitalavailable = '{$capitalavailable}'
                              WHERE companies.companytag = '${ctag}'";

 

hope this helps

 

[PhpMyAdmin Password]

what version of mysql are you running?

[Make Currency an Integer]

I would use preg_replace()

[Problem after forum installation]

I tried to correct for any mistake but could not find any since I do not know much. I need your help please. Here is the file section. BTW, Is line 1 <?php ???

 

yes it is considered a line

[form action with strings......]

the only way that i know of is to use the onchange event using javascript...i highly doubt that it would work since you are using php however..

[POST Data, Forms, and Database]

in your first script..the name of your <select> is "page"...so wouldnt it be $_POST['page'] not $_POST['num']?

[POST Data, Forms, and Database]

this

<input name="name" type="text" class="form1" value="About Us" maxlength="20" id="name" /><br /><br />

 

corresponds to this

$name=$_POST['name'];

 

because you have an input with the same name...on the first scripts that you showed me...the only input that you have on that page is the submit button...so that is the only value that will fill the $_POST array...

 

[POST Data, Forms, and Database]

yes I editted my answer as I saw this after I posted...but to get that the $num value...it isnt actually passed from the form...you would set up another query like the one that you did in the first script..and use the $row['num'] value to make your second query

[POST Data, Forms, and Database]

the $_POST array will not have anything to do with values from mysql

[POST Data, Forms, and Database]

im confused as to where you are getting $_POST['num']; from...in order for that to work..you would need to have an input in you first form on with the name of "num".... what value are you trying to pass to pageedit.php?

[POST Data, Forms, and Database]

what is the exact line that is giving this error?

[how to show no match found]

this will check to see if there are any rows grabbed....if there arent any rows...it will echo "no match found"

[how to show no match found]

you could add this to you code

 

$num_rows = mysql_num_rows($sql);
if ($num_rows == 0)  {

   echo "No Match Found";
}
else  {

....
}