Jump to content


  • Posts

  • Joined

  • Last visited

Everything posted by phppup

  1. I suppose it is VERY DIFFICULT to alter the orientation if none is detected. Do smartphones use a different method of orientation? Could uploading an image remove the data?
  2. What is the difference in result between echo '<pre>', print_r($exif, 1), '</pre>'; and echo '<pre>', print_r($exif), '</pre>';
  3. BEFORE Array ( [FileName] => myTest.jpg [FileDateTime] => 1574967654 [FileSize] => 12566 [FileType] => 2 [MimeType] => image/jpeg [SectionsFound] => COMMENT [COMPUTED] => Array ( [html] => width="500" height="244" [Height] => 244 [Width] => 500 [IsColor] => 1 ) [COMMENT] => Array ( [0] => CREATOR: gd-jpeg v1.0 (using IJG JPEG v62), quality = 80 ) ) AFTER Array ( [FileName] => myTest.jpg [FileDateTime] => 1574967654 [FileSize] => 12566 [FileType] => 2 [MimeType] => image/jpeg [SectionsFound] => COMMENT [COMPUTED] => Array ( [html] => width="500" height="244" [Height] => 244 [Width] => 500 [IsColor] => 1 ) [COMMENT] => Array ( [0] => CREATOR: gd-jpeg v1.0 (using IJG JPEG v62), quality = 80 ) )
  4. The test image is on the server in an upload folder which is in the same folder as this script (above). I confirmed connectivity to the image by printing EXIF data, but the image did not change. If it were overwritten, then the image file's 'last modified' info would change. For some reason, nothing is being altered or created from the original file. Do I need to move or create a line in the script?
  5. I'm going to have to double check it. My image was not being rotated and overwritten. Nor was a new file being created.
  6. So how come I am getting no result and you have success? What an I missing? How do I transfer the unaltered pieces of EXIF data? I've read multiple webpages. Most accept that it's lost in the rotation process, but that seems somewhat of a lazy inevitability.
  7. Yes, I am going to try that. If I'm understanding correctly, the script checks the orientation inside the EXIF and then changes the degrees of rotation accordingly. Does the new image then contain EXIF info that head been adjusted to reflect the new orientation?
  8. I'm not sure what you mean. I think I need to compare the code with the test image's EXIF info, but not sure how to get that either.
  9. Is there a benefit to keeping my form and the PHP that processes it within a single file?
  10. I have some photos that were taken using a cellphone in an upright/vertical position. They were downloaded and placed in a folder to be viewed on a webpage but they displayed horizontally/sideways (with the persons head on the left). I am assuming that the EXIF information in the image tells it which side is up and what the intended 'top' of the picture should be.. I want to have a PHP function that will rotate the image to its intended display position so that photos of mountain ranges [intentionally holding the smartphone sideways] are horizontal and portraits [where the smartphone in upright] are vertical. I placed this code in a PHP file but got no change in the image: function correctImageOrientation($filename) { if (function_exists('exif_read_data')) { $exif = exif_read_data($filename); if($exif && isset($exif['Orientation'])) { $orientation = $exif['Orientation']; if($orientation != 1){ $img = imagecreatefromjpeg($filename); $deg = 0; switch ($orientation) { case 3: $deg = 180; break; case 6: $deg = 270; break; case 8: $deg = 90; break; } if ($deg) { $img = imagerotate($img, $deg, 0); } // then rewrite the rotated image back to the disk as $filename imagejpeg($img, $filename, 95); } } } } $filename = 'upload/myTest.jpg'; correctImageOrientation($filename); Am I using the correct approach to get the desired result? Is the code correct?
  11. I don't have access to my computer at the moment, but... The first script is a basic HTML form (with some JS and CSS links) that is saved as a PHP file. To combine them, I have simply cut and pasted the form code (in its entirety) below the PHP code (displayed previously). I have not changed any file names or paths. Also, after deeper investigation, I saw a line in a jQuery file (not my forte) that was written as "data.html" . Is it possible that it is falling to find "data" because AFTER my modification there is no longer an HTML file? If this is true, can I redirect it to the PHP file? Perhaps a better question would be "What is the benefit to keeping my form and the PHP that process it within a single file? Thanks for the help and HAPPY THANKSGIVING.
  12. I already have a working PHP/HTML uploading form that I've been working on and tweaking as a single PHP file. Now, I am attempting to integrate a progress bar. It seems almost impossible to find a working script to show the progress of multiple files as they upload. However, I have one that is "good enough" and have broken it down thusfar so that I can effectively integrate it into my working script. At this point, (aide from the JQuery, CSS, etc.) it consists primarily of two files: The first is a PHP file containing the form and basic links for function and style. The second is a PHP upload file that is handling the "heavy lifting." I have broken it down to this: $dir = 'uploads/'; $count = 0; if ($_SERVER['REQUEST_METHOD'] == 'POST' and isset($_FILES['files'])) { // loop all files foreach ( $_FILES['files']['name'] as $i => $name ) { // now we can move uploaded files if( move_uploaded_file($_FILES["files"]["tmp_name"][$i], $dir . $name) ) $count++; } echo json_encode(array('count' => $count)); } No names or file locations have been changed and it functions as originally designed in this condition. However, if I combine the first file with this file, I loose the echo json_encode(array('count' => $count)); result, which is expanded in another file to be a final message of "You have uploaded $count files successfully." What am I doing wrong or missing? Is there an easier way to do this? A link to a fancy progress bar for multiple file upload would be wonderful, as most that I've found actually do not work.
  13. The link you posted does not connect to a definitive article. Please double check it.
  14. I have an index HTML form that has a JavaScript link and action = 'xyz.php' Everything works fine. I've seen PHP scripts with HTML form after the closing tag ?> and they work. Yet when I included my HTML g form after my PHP code, some of my JS stopped working. What are the protocols to combining PHP and HTML? Which should run first? When is the action run?
  15. Thanks greatly to cyberRobot. Using the diagnostic PRINT line assured me that the UPLOAD is being grabbed and effectively moving files. Now I need to focus on the code. At this point, I think these lines are where my problem lies if($dir = opendir($startingFolder)){ while(($file = readdir($dir))!== false){ The original scripting (which works) is designed to take folders from an established folder rather than from an upload. So my thinking is that I need to initiate a transition. I have tried replacing these lines with foreach ($_FILES["upload"]["error"] as $key => $error) { $tmp_name = $_FILES["upload"]["tmp_name"][$key]; if (!$tmp_name) continue; $name = basename($_FILES["upload"]["name"][$key]); if ($error == UPLOAD_ERR_OK) { but that is apparently incorrect. What coding can I use to bridge the gap to allow the uploaded files to continue through the scripted process?
  16. I am double checking my code and I have had the correct syntax in place (ie: $startingFolder = $_FILES['upload']; ) yet I am not getting a result unless a switch back to $startingFolder = 'myLocalstorage/'; (at which point everything runs fine. Is there a diagnostic or echo that I can use to confirm a connection to the uploading items. My upload is confirming that the items are selected, but I am not receiving a success message nor am I seeing a result in my destination folder when I upload.
  17. In actuality the quotes are in the correct location. It's the damn software that I am trying to use to create the post that keeps shifting things. $startingFolder = $_FILE['upload']; ['justsinglequotesethere'] But I still am not getting any results. PS: should echo $startingFolder give me the name of the tmp folder or list its contents? What do I need to complete the connection? I HATE AUTOCORRECT. yez, I h@te it soooo much.
  18. Thanks to all, but I am still confused. I have read both Barand's references earlier, and in fact have quotes on my array index. Am I correct in expecting $startingFolder = '$_FILE['upload']; to work as a valid replacement to $startingFolder = 'LocalFolder/' or am I missing something. Isn't the code that effectively loops through the folder's files adequate to loop through the array? Should I be linking to the tmp folder instead?
  19. I have a PHP script that modifies images that are stored in a local folder related to $startingFolder. Essentially, I can use $startingFolder = 'anyFolder/'; $finalFolder = 'endResult/'; To manage the variables and direct the source and destination of the scripts actions from this starting point. I'm trying to extend my capabilities so that I can use the script while uploading images. Rather than UPLOAD several images to $startingFolder and then run the script, I thought it would be more efficient to handle this in one script. However, I am having trouble making the CONNECTION so that this can be accomplished. What is the proper way to 'grab' the files during upload? How can I access the files during the process? I have a working HTML <input type='file' name='upload[]' multiple > And have tried $startingFolder = '$_FILE[upload]'; but I am missing the mark somewhere. Please help.
  20. After a lot of reading and some progress, there are now a whole new set of questions that have emerged. So this thread requires more discussion and opinion for guidance, rather than actual code solutions. I have found different approaches to uploading image files. Some upload directly to a destination folder. Some upload to a database. Some do both. It seems more practical to upload image files to a folder (although I do recognize the bonus of having information about the individual files stored for reference), but is there a benefit to using one instead of the other? For space? Speed? Other implementations?
  21. That's exactly what I was trying to avoid. LoL. Thanks.
  22. So a decent script would include a php file that connects to the server, and validates the file type or 'scrubs it' for security purposes?
  23. Are you saying that even if the JavaScript is on the server, it will not be able to put the image files on the same server?
  24. An obvious answer would be ok. Sometimes the most difficult solutions are in plain sight. I am not doing the images in a database, so I am looking at JS scripting. I want sure if the destination folder is required to be at the top of a script, or file some specific guidelines. I'm sure I'll eventually find the answer, but I was hoping for a clue that might help me save some time.
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.