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Everything posted by Sparkon

  1. Hi guys. I'm new here and I am also new to php, and I need help about something. So I have this basic piece of code in my html file <input type="file" id="plg_upload" name="filename"> <input type="submit"> And I found this code for FTP uploads // FTP access parameters $host = 'hostexample.com'; $usr = 'user'; $pwd = 'pass'; // file to move: $local_file = './example.txt'; $ftp_path = '/data/example.txt'; // connect to FTP server (port 21) $conn_id = ftp_connect($host, 21) or die ("Cannot connect to host"); // send access parameters ftp_login($conn_id, $usr, $pwd) or die("Cannot login"); // turn on passive mode transfers (some servers need this) // ftp_pasv ($conn_id, true); // perform file upload $upload = ftp_put($conn_id, $ftp_path, $local_file, FTP_ASCII); // check upload status: print (!$upload) ? 'Cannot upload' : 'Upload complete'; print "\n"; /* ** Chmod the file (just as example) */ // If you are using PHP4 then you need to use this code: // (because the "ftp_chmod" command is just available in PHP5+) if (!function_exists('ftp_chmod')) { function ftp_chmod($ftp_stream, $mode, $filename){ return ftp_site($ftp_stream, sprintf('CHMOD %o %s', $mode, $filename)); } } // try to chmod the new file to 666 (writeable) if (ftp_chmod($conn_id, 0666, $ftp_path) !== false) { print $ftp_path . " chmoded successfully to 666\n"; } else { print "could not chmod $file\n"; } // close the FTP stream ftp_close($conn_id); I am using provided code in my .php file that is POST called. How can I pass the information about file I want to upload from html page to this .php file? I know how to pass strings, field results, etc. But never worked with the files.
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