Hi guys. I'm new here and I am also new to php, and I need help about something.
So I have this basic piece of code in my html file
<input type="file" id="plg_upload" name="filename">
<input type="submit">
And I found this code for FTP uploads
// FTP access parameters
$host = 'hostexample.com';
$usr = 'user';
$pwd = 'pass';
// file to move:
$local_file = './example.txt';
$ftp_path = '/data/example.txt';
// connect to FTP server (port 21)
$conn_id = ftp_connect($host, 21) or die ("Cannot connect to host");
// send access parameters
ftp_login($conn_id, $usr, $pwd) or die("Cannot login");
// turn on passive mode transfers (some servers need this)
// ftp_pasv ($conn_id, true);
// perform file upload
$upload = ftp_put($conn_id, $ftp_path, $local_file, FTP_ASCII);
// check upload status:
print (!$upload) ? 'Cannot upload' : 'Upload complete';
print "\n";
/*
** Chmod the file (just as example)
*/
// If you are using PHP4 then you need to use this code:
// (because the "ftp_chmod" command is just available in PHP5+)
if (!function_exists('ftp_chmod')) {
function ftp_chmod($ftp_stream, $mode, $filename){
return ftp_site($ftp_stream, sprintf('CHMOD %o %s', $mode, $filename));
}
}
// try to chmod the new file to 666 (writeable)
if (ftp_chmod($conn_id, 0666, $ftp_path) !== false) {
print $ftp_path . " chmoded successfully to 666\n";
} else {
print "could not chmod $file\n";
}
// close the FTP stream
ftp_close($conn_id);
I am using provided code in my .php file that is POST called.
How can I pass the information about file I want to upload from html page to this .php file? I know how to pass strings, field results, etc. But never worked with the files.
