[[SOLVED] Variable with spaces]

Just put quotes around the PHP Statement and you should be set.

[Adding Required Imputs to this page]

if(!$_POST['submit']){
echo "<form method=post action=thispage.php>\n";
echo "Teacher Name: <input type=text name=tname><br>\n";
echo "Room #: <input type=text name=room><br>\n";
echo "<input type=submit name=submit value=go>\n";
echo "</form>\n";
}else {
$teacher = $_POST['tname'];
$room = $_POST['room'];

  if($teacher && $room){
  //do this
  }else {
  //not supplied
  }
}

[[SOLVED] Form problem]

Try putting the text field before the submit field.

[[SOLVED] Trying to create search page Warning: mysql_fetch_array(): supplied argument is]

Why not use a switch for that.

 

switch($row_userinfo['level']){
    case 1: $level = "User"; break;
    case 3: $level = "Admin"; break;
    default: $level = "User";
}

echo $level;

[[SOLVED] Trying to create search page Warning: mysql_fetch_array(): supplied argument is]

$search = mysql_real_escape_string($_GET[search]);
$sql = "SELECT * FROM `phones` WHERE `make` LIKE '%$search%' OR `model` LIKE '%$search%'";
$result = mysql_query($sql) or die(mysql_error());

[[SOLVED] Run Code Only Once After Array Completes]

Once the part before the sleep(10); line occurs all that data will be loaded. And after 10 seconds of cooling down, the part after that line will load then.

[What is the '@' symbol in php]

Suppresses error reporting.

[script help.]

We can't help without some source.

[[SOLVED] Run Code Only Once After Array Completes]

//do this first
sleep(10); //relax the script for 10 seconds
//do second thing

[W.T.F.?]

//uncomment the $tot
if($tot >= 1){
//show contacts
}else {
//no contacts
}

[game reporting issue]

The values obviously don't exist, there would be content within the single quotes if the variables had a string value.

[game reporting issue]

The values are blank. And you don't need that comma before calling the WHERE operator.

 

print_r($_POST)

[switch statement doesn't work on Mac]

Why not use a dropdown? Lol. It looks fine to me.

 

$array = array('edit','delete','change');

if(!$_GET['action'] || !in_array($_GET['action'],$array)){
echo "<form name=\"switch\" method=\"get\" action=\"switch.php\">\n";
echo "Option: <select name=\"action\">\n";
    foreach($array AS $options){
    echo "<option value=\"$options\">".ucfirst($options)."</option>\n";
    }
echo "</select> <input type=\"submit\" value=\"Switch Away Captain\"></form>\n";
}else {

switch($_GET['action']){
case edit: echo "omfg edit"; break;
case delete: echo "omfg delete"; break;
case change: echo "omfg change"; break;
default: echo "omfg wtf";
}

}

[syntax coloring in vi editor]

Best try would be going into Command Mode, ESC + :, then enter the line "syntax on" [remove quotes]

[database tables]

NULL or 0 is supplied as an unknown value. So using "NOT NULL" there's going to be a supplied value why entering the data into the field.

[foreach problems]

Also, when you're defining the values in the foreach statement give them names that have a line break or something, so they don't get all cluttered.

[foreach problems]

Well duh, make sure you're passing the field as an array.

 

<input type="checkbox" name="sexy[]" id="1-3">

[[SOLVED] PHP / MYSQL - 2 COL Result Formatting]

I just provided an easier example.

[[SOLVED] PHP / MYSQL - 2 COL Result Formatting]

$sql = "SELECT * FROM `this` WHERE `that`='grapejuice'";
$res = mysql_query($sql) or die(mysql_error());

while($row = mysql_fetch_assoc($res)){
$first = $row['first'];
$last = $row['last'];
$dname = $row['displayname'];
$picurl = $row['pictureurl'];
echo "Like hello your name is $first $last, your display name is $dname and your picurl is $picurl, get used to it!\n";
}

 

Might I add if you're going to use the $i < $num, make sure the less than sign has the inequality of less than or equal to. Because 1 < 3 will produce results 1 and 2.

[PHP Functions and Queries]

What variables exactly?

[[SOLVED] true type fonts not working]

Correct.

[[SOLVED] true type fonts not working]

Does the path exist? Try using file_exists(); to see if that file even exists.

[Searching using a database]

<?php
if(!$_POST[submit]){
echo "<form name=\"this\" action=\"index.php\" method=\"post\">place: <input type=\"text\" name=\"place\">\n";
echo "<input type=\"submit\" value=\"GO GO GO\" name=\"submit\"></form>\n";
}else {
$place = $_POST['place'];

if($place){
	$sql = "SELECT * FROM `tbl` WHERE `place` LIKE '%$place%'";
	$res = mysql_query($sql) or die(mysql_error());
		if(mysql_num_rows($res) == 0){
		echo "no results\n";
		}else {
			while($row = mysql_fetch_assoc($res)){
			echo "place name: $row[place] | some other field: $row[field1]<br>\n";
			}
		}
}else {
echo "omg no place\n";
}
}
?>

 

modify it to your extent

[[SOLVED] true type fonts not working]

Are you outputting the data into an image?

[[SOLVED] wont add to mysql db]

You're saying you can't add the info to the database? Is all your POST data correct? (e.g., the field names)

 

Have you tried using "or die(mysql_error())" on the actual insert query?