The error message I am getting says it can't open the url that I put on line 22 for today's date. I try using real url's not the ones below. It gives me the correct address for it, but it won't open it. It says suitable wrapper can't be found even though my include command works fine, otherwise it wouldn't bring up slot 22's web address. I've tackled php include commands and now know how to do it really well, so there is still something wrong with the script. PS. I changed it to this in my php. $date = date('d'); include($content[$date]); Any ideas? I notice this has no brackets surrounding any commands, does it need any? Thanks Here is the one I am trying now before I try trimming it down. <?php $content = array(); $content["01"] = "day1.htm"; $content["02"] = "day2.htm"; $content["03"] = "day3.htm"; $content["04"] = "day4.htm"; $content["05"] = "day5.htm"; $content["06"] = "day6.htm"; $content["07"] = "day7.htm"; $content["08"] = "day8.htm"; $content["09"] = "day9.htm"; $content["10"] = "day10.htm"; $content["11"] = "day11.htm"; $content["12"] = "day12.htm"; $content["13"] = "day13.htm"; $content["14"] = "day14.htm"; $content["15"] = "day15.htm"; $content["16"] = "day16.htm"; $content["17"] = "day17.htm"; $content["18"] = "day18.htm"; $content["19"] = "day19.htm"; $content["20"] = "http://www.website.com"; $content["21"] = "http://www.website.com"; $content["22"] = "http://www.website.com"; $content["23"] = "http://www.website.com"; $content["24"] = "http://www.website.com"; $content["25"] = "day25.htm"; $content["26"] = "day26.htm"; $content["27"] = "day27.htm"; $content["28"] = "day28.htm"; $content["29"] = "day29.htm"; $content["30"] = "day30.htm"; $content["31"] = "day31.htm"; $date = date('d'); include($content[$date]); ?>