[[SOLVED] preg_match_all returns only one match]

Regular expressions are not the best tool for nested data, but this works:

 

<pre>
<?php

$data = <<<DATA
<custom>
    probe1
    <custom>
        probe2
    </custom>
    probe3
</custom>
<custom>
    probe4
</custom>
<custom>
    probe5
</custom>
DATA;

preg_match_all('%<custom>(??!<custom>)(?!</custom>).)*<\/custom>%s', $data, $matches);
print_r($matches);

?>
</pre>

[quoted numbers preg_replace]

$sql = preg_replace("/'(\d+)'/", '$1', $sql);

[Regex doesn't stop when it needs to.]

You have a laziness/greediness issue.

[Replace Unless...]

?! means does not follow.

?= means follows.

?!=, what you have, means does not follow, then a literal =.

[Where can I find an absolute idiots guide to Perl programming language online?]

http://learn.perl.org

[Stopping all non english characters]

What encoding are you using?

[Replace Unless...]

http://www.regular-expressions.info/lookaround.html

[[SOLVED] match separator and format a date]

/(\.|-|\/)+/

 

Why are you using this and not a character class? This kind of alternation is not optimal.

[[SOLVED] match separator and format a date]

I think it's best to include the + since it doesn't hurt. If the data is coming from a user they could have a typo—"02/27//2009" for instance—which, when split, would create 4 elements rather than 3. However, if there are any delimiters on the ends, this would still create empty elements. I recommend:

 

preg_split('/\D+/', $string, -1, PREG_SPLIT_NO_EMPTY)

[[SOLVED] match separator and format a date]

You can split on \D+.

[need help splitting where 2 carriage returns exist]

file_get_contents should be fine. Most editors do; I use Notepad++.

[Formatting question with semicolons]

<pre>
<?php

$tests = array(
	'BBB',
	'BBB; BBB',
	'BBB; BBB; BBB; BBB',
	'B;',
	';B',
	';;',
);

foreach ($tests as $test) {
	echo "$test => ";
	echo preg_match('/\A([^;]+;\s*)*[^;]+\z/', $test) ? 'OK' : 'Not OK' ;
	echo '<br>';
}

?>
</pre>

[need help splitting where 2 carriage returns exist]

<pre>
<?php

$data = <<<DATA
HOW TO WATER ROSES

Start by turning the water on....

HOW TO MOW

Start the mower...
DATA;

print_r(preg_split('/(?:\r?\n)+/', $data));

?>
</pre>

[[SOLVED] Regex with a "Degree" character?]

You need to use the /m modifier if you want $ to match around all new lines, rather than just the end of the string.

[Regex for pub id]

/\Apub-\d{16}\z/

[PHP is adding ? to unicode values]

What's the value of $unicode?

 

This gives me "réréré":

 

<meta http-equiv="Content-Type" content="text/html;charset=UTF-8">
<pre>
<?php
$text = 'r%C3%A9r%C3%A9r%C3%A9';
echo urldecode($text);
?>
</pre>

[PHP is adding ? to unicode values]

"Suddenly"? Perhaps your input and/or code changed? Have you examined the data fully? A hex dump, perhaps?

[PHP is adding ? to unicode values]

You've bad Unicode. See "Replacement character" here.

[RegExp to parse links]

Your first .*? will capture anything up to prodID, even it has to go beyond another double quote or into another tag.

 

Try |href="([^"]+prodID=[^"]+)"[^>]*>(.*?)</a>|.

[Japanese+Regex+PHP getting Kanji characters]

Are all of these Kanji? You can use their code point ranges to match them, e.g. preg_match_all('/[\x{3000}-\x{303F}]+/u', $string, $matches);.

[[SOLVED] Storing "Non-English" characters under MySQL]

http://www.phpfreaks.com/forums/index.php/topic,190618.msg855845.html#msg855845

[[SOLVED] preg_match_all not working]

Turn your warnings on: Warning: preg_match_all() expects parameter 2 to be string, array given.

You need to examine the results; I recommend print_r($byname);

[[SOLVED] Regex Problem]

use lazyiness

'/href="(.*?)"/i'

 

Even better, be specific: '/href="([^"]*)"/i'

 

in the regex above, you are taking into consideration escaped quotes

 

The double quotes were escaped in the regex because they were used to delimit the string; they will match an unescaped quote:

 

<pre>
<?php
  $str = '"';
  echo preg_match("/\"/", $str);
?>
</pre>

[hi-2 help with regex]

Apparently it requires the delimiter:

 

preg_match('/' . preg_quote($start, '/') . '(.*?)' . preg_quote($end, '/') . '/', $data, $matches);

[[SOLVED] Using Negation and Alteration In Regex]

/(\b(?!(?:else)?if)\S+\b\s*\()/