DeanWhitehouse

yer, u would have to make the bbcode regex in javascript

I think you need AJAX

do you mean where the bbcode is applied instantly?

in login.php try having session start at the top. and also add error_reporting(E_ALL); to the top of the page and check if there are any errors and add die statements to the querys

change $htmlcode = '<a href=' . $linkurl . '><img src=' . $imgurl . '></a>'; to $htmlcode = '<a href="' . $linkurl . '"><img src="' . $imgurl . '"></a>';

erm the safest way would be a selection of options . e.g. allow them to select a background colour from a drop down list , instead of allowing them to enter any code.

This would be easy to get past if they have javascript disabled, unless you have all the links disabled to begin with.

what do you mean all this stuff, you will need to set up bbcode in PHP then just save the data in the textarea in the db

or another option <?php if (!$_SESSION['firsttime']) { echo "<center><font size='10' color='#00FFFF' weight='bold'>Welcome</font></center>"; $_SESSION['firsttime'] = true; } ?>

I have never seen a tutorial for this, and if you are as good as you say with Javascript and ajax this should be easy Here is a link to one i started, with little javascript knowledge http://americangangsters.org/bbcode.php Also this is the wrong forum, it has nothing to with php

people never read the post near the top about header errors. And click topic solved if solved

or simple way would be to use sessions , as they will be destroyed when the browser is closed. Or they timeout after 30 minutes i think

This is only advised when the site is running live, not in development. Also your mysql_query's may cause errors if u have set them to die on error.

add die to all your querys

first off post all your code

this is wrong <?session_start(); include("database.php"); if($_SESSION['username']) { $query = "SELECT * FROM virtuala WHERE username='{$_SESSION['username']}'"; $result = mysql_query($query); } $admin = $row['admin']; ?> it should be , short tag should not be used <?php session_start(); include("database.php"); if($_SESSION['username']) { $query = "SELECT * FROM virtuala WHERE username='{$_SESSION['username']}'"; $result = mysql_query($query); } $admin = $row['admin']; ?>

ok then add one in PHP my admin or ure database managment program

is the field name correct? and/or try $signature = $userinfo['signature']; // this doesnt

what? your question doesnt make any sense

if you want an easy fix put ob_start(); at the top of the page

Read this http://www.phpfreaks.com/forums/index.php/topic,37442.0.html

do you even have a database created on the server?

ok, this is the function i have made <?php function crime_chance() { $userid = $_SESSION['userid'] ; $row = mysql_fetch_assoc(mysql_query("SELECT * FROM users WHERE ID = '{$userid}'")); $chance = $row['crime_chance']; $random_chance = rand(0,100); echo $random_chance."<br>"; echo $chance; if ($chance >= $random_chance ) { $success = 1; } elseif($random_chance <= $chance) { $success = 0; } if($chance == 100) { $success = 1; } if($success == 1) { echo "<tr><td>Succeeded</td></tr>"; } else { echo "<tr><td>Failed</td></tr>"; } $add = rand(1,2); echo "<tr><td>Percent to add to exp ".$add. "</td></tr>"; } ?> Explanation of the game , what it will be is each time you commit a crime you gain either 1 or 2 percent more experience, and the chance of succeeding is based on how much experience you have. But the script we have i dont think it is very good, am i wrong ?

Are you using a mysql database or mysqli?

I am trying to make a script that will , depending on your experience , you will either succeed or fail. so for example if you have 15.5% experience you have a better chance of winning than if you had less. Any ideas, i cant work out any logic for this.