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DeanWhitehouse

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Posts posted by DeanWhitehouse

    [SOLVED] check box, problem 2

    in PHP Coding Help

    Posted

    with this code

    }
if(isset($_POST['hideemail']) == 0)
{
mysql_query("UPDATE $user 
SET show_email = '0' 
WHERE user_id = '$user_id'")or die('Could not change settings: ' . mysql_error());
}
elseif(isset($_POST['hideemail']) == 1)
{
mysql_query("UPDATE $user 
SET show_email = '1' 
WHERE user_id = '$user_id'")or die('Could not change settings: ' . mysql_error());
}
echo "Settings Saved";
}

     

    its changing the show_email even when i don't tick either box, it shouldn't be doing this, it should only do this if it is ticked.

     

    Dynamically update on a page with forms?

    in PHP Coding Help

    Posted

    are there any errors, and change the code to this.

    <?php
$company = $_POST['company'];
$name = $_POST['name'];
$city = $_POST['address'];
$postal = $_POST['postal'];
$tel = $_POST['tel'];
$email = $_POST['email'];
$comments = $_POST['comments'];

if(isset($_POST['submit']))
{
echo "$company<br>$name<br>$city<br>$postal<br>$tel<br>$emaili<br>$comments"; // add anything you want displayed
}
else
{

?>
<u>Input a user</u>
<br />
<form method="post" action='<?php $_SERVER['PHP_SELF']; ?>'>
<table>
<tr>
<td>Company:
<td><input type="text" name="company">
</tr>
<tr>
<td>Name:
<td><input type="text" name="name">
</tr>
<tr>
<td>Address: 
<td><input type="text" name="address">
</tr>
<tr>
<td>City: 
<td><input type="text" name="city">
</tr>
<tr>
<td>Postal Address: 
<td><input type="text" name="postal">
</tr>
<tr>
<td>Telephone Number: 
<td><input type="text" name="tel">
</tr>
<tr>
<td>Email Address: 
<td><input type="text" name="email">
</tr>
<tr>
<td>Comments: 
<td><input type="text" name="comments">
</tr>
<tr>
<td><input type="submit" value="Submit">
</tr>
</table>
<?php
}
?>

     

    first of all and once this bit works, work on the search.

     

    Dynamically update on a page with forms?

    in PHP Coding Help

    Posted

    ok, let me change the code a bit

    <?php
$company = $_POST['company']
$name = $_POST['name']
$city = $_POST['address']
$postal = $_POST['postal]
$tel = $_POST['tel']
$email = $_POST['email']
$comments = $_POST['comments']

if(isset($_POST['submit']))
{
echo $company<br>$name<br>$city<br>$postal<br>$tel<br>$email<br>$comments; // add anything you want displayed
}
else
{
?>
<html>
<body>
<form action='<?php $_SERVER['PHP_SELF']; ?>' method='POST'>
<table>
<tr>
        <td>Company:
        <td><input type="text" name="company">
</tr>
<tr>
        <td>Name:
        <td><input type="text" name="name">
</tr>
<tr>
        <td>Address:
        <td><input type="text" name="address">
</tr>
<tr>
        <td>City:
        <td><input type="text" name="city">
</tr>
<tr>
        <td>Postal Address:
        <td><input type="text" name="postal">
</tr>
<tr>
        <td>Telephone Number:
        <td><input type="text" name="tel">
</tr>
<tr>
        <td>Email Address:
        <td><input type="text" name="email">
</tr>
<tr>
        <td>Comments:
        <td><input type="text" name="comments">
</tr>
<tr>
        <td><input type='submit' value='Submit' name='submit' />
</tr>
</table>
<?php
}
?>

    [SOLVED] check box, only check if user checked

    in PHP Coding Help

    Posted 

    if(isset($_POST['update']))
{
if($user_email)
{
	if($user_email == $user_email2)
	{
	mysql_query("UPDATE $user 
SET user_email = '$user_email' 
WHERE user_id = '$user_id'")or die('Could not update email: ' . mysql_error());
	}
	else
	{
	echo "Email Addresses do not match";
	}
}
if($user_password)
{
	if($user_password == $user_password2)
	{
	mysql_query("UPDATE $user 
SET user_password = '$user_password' 
WHERE user_id = '$user_id'")or die('Could not change password: ' . mysql_error());
	}
	else
	{
	echo "Passwords do not match";
	}
}
if(isset($_POST['hideemail']))
{
mysql_query("UPDATE $user 
SET show_email = '0' 
WHERE user_id = '$user_id'")or die('Could not change settings: ' . mysql_error());
}
elseif(isset($_POST['hideemail']))
{
mysql_query("UPDATE $user 
SET show_email = '1' 
WHERE user_id = '$user_id'")or die('Could not change settings: ' . mysql_error());
}
}



?>
<html>
<table bgcolor='#999999' align='center' width="400px">
<form action='<?php $_SERVER['PHP_SELF']; ?>' method='POST'>
<tr><td width="10px">Maximum Length<br /> 20 characters.</td></tr>
<tr><td width="10px">E-mail Address:</td> <td><input type='text' name='user_email' value="<?php echo "$email"; ?>"  /><br /></td></tr>
<tr><td width="10px">Confirm E-mail Address: </td><td><input type='text' name='user_email2' value="<?php echo "$email"; ?>" /><br /></td></tr>
<tr><td width="10px">Maximum Length<br /> 30 characters.</td></tr>
<tr><td width="10px">New Password:</td><td> <input type='password' name='user_password' maxlength="30" /><br /></td></tr>
<tr><td width="10px">Confirm Password:</td><td> <input type='password' name='user_password2' maxlength="30" /><br /></td></tr>
<tr><td width="10px">Hide Email</td><td width="10px">Yes<input type="radio" value="0"  name="hideemail"/> No<input type="radio" value="1"  name="hideemail"/> </td></tr>
<tr><td><input type='submit' value='Save Changes' name='update' /></td>
</form>
</table>
</html>

     

    this is my code for the page where they can check the box, i want it so that if they check one it updates the database and if another updates it differently

    Dynamically update on a page with forms?

    in PHP Coding Help

    Posted

    so if im right? you want to display what they enter in the form on the page, try this

    <?php
$array = array("company","name","address","city","postal","tel","email","comments");
// i've never used arrays so im not sure if this way works
if(isset($_POST['submit']))
{
echo $array["company"]; // add anything you want displayed
}
else
{
?>
<html>
<body>
<form action='<?php $_SERVER['PHP_SELF']; ?>' method='POST'>
<table>
<tr>
        <td>Company:
        <td><input type="text" name="company">
</tr>
<tr>
        <td>Name:
        <td><input type="text" name="name">
</tr>
<tr>
        <td>Address:
        <td><input type="text" name="address">
</tr>
<tr>
        <td>City:
        <td><input type="text" name="city">
</tr>
<tr>
        <td>Postal Address:
        <td><input type="text" name="postal">
</tr>
<tr>
        <td>Telephone Number:
        <td><input type="text" name="tel">
</tr>
<tr>
        <td>Email Address:
        <td><input type="text" name="email">
</tr>
<tr>
        <td>Comments:
        <td><input type="text" name="comments">
</tr>
<tr>
        <td><input type='submit' value='Submit' name='submit' />
</tr>
</table>
<?php
}
?>

    [SOLVED] check box, only check if user checked

    in PHP Coding Help

    Posted

    in case the title didn't make sense , i will explain.

    how can i have it so if a user checks a box it stays checked and if they don't check it , it isn't checked??

    also is there a way to have multiple check boxes with the same, but then how can i differ them when using an if(isset($_POST['']))

    function as they have the same name(how else can they be intetifed)

    [SOLVED] User Profiles

    in PHP Coding Help

    Posted

    no, db_connect.php has the session_start() on it also when i try to echo like this

    <?php
require_once 'db_connect.php';
require_once 'nav_bar.php';
require_once 'logged_in.php';

$user_id = $_SESSION['user_id'];
$sql = "SELECT * FROM $user WHERE `user_id`='{$user_id}' LIMIT 0,1;";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
$username = $row['user_name']

echo "$username";
?>

     

    i get an "unexpected" error with this, it doesn't expect the echo

    [SOLVED] User Profiles

    in PHP Coding Help

    Posted

    this code is right but, it doesn't display anything from the database

    <?php
require_once 'db_connect.php';
require_once 'nav_bar.php';
require_once 'logged_in.php';

$user_id = addslashes($_GET['id']);
$sql = "SELECT * FROM `$user` WHERE `user_id`='{$user_id}' LIMIT 1;";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
$username = $row['user_name']

?>

    i tried changing it to this but, it still isn't displaying anything

    <?php
require_once 'db_connect.php';
require_once 'nav_bar.php';
require_once 'logged_in.php';

$user_id = $_SESSION['user_id'];
$sql = "SELECT * FROM $user WHERE `user_id`='{$user_id}' LIMIT 0,1;";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
$username = $row['user_name']

?>

    do i need to echo it?

    [SOLVED] User Profiles

    in PHP Coding Help

    Posted

    i get this error

    Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/www/deanwhitehouse.awardspace.co.uk/test/user_profile.php on line 9

     

    with this code

    <?php
require_once 'db_connect.php';
require_once 'nav_bar.php';
require_once 'logged_in.php';

$user_id = addslashes($_GET['id']);
$sql = "SELECT * FROM `$user` WHERE `id`='{$user_id}' LIMIT 1;";
$result = mysql_query($sql);
$row = mysql_fetch_assoc($result);
$username = $row['user_name']

?>

    [SOLVED] User Profiles

    in PHP Coding Help

    Posted

    i have this code for the user profile link

    <a href='user_profile.php?id=<?php echo $_SESSION['user_id']; ?>'>Settings</a><br>

    now on the user_profile.php page how do i display this users profile, can i call all there details from the database using there user_id

    [SOLVED] dynamic logout

    in PHP Coding Help

    Posted

    i think its the right title, anyhow

    how can i make a login code so the link is like

    <a href="whateverpageon?logout">Logout</a>

    instead of my

    <a href="logout.php">Logout</a>

    basically ,so that when they logout they are kept on the same page

     

    php login

    in PHP Coding Help

    Posted

    try this

    <?php
session_start();
if ($_SESSION['logged_in'] == true){
echo "You are logged in.";
}
else 
{
echo "You are not logged in.";
}
?>

    and this

    <?php
session_start();
$username = "lemon";
$password = "123";
if ($_POST['txtUsername'] != $username || $_POST['txtPassword'] != $password) {
?>
<form name="login" method="post" action="<?=$_SERVER['PHP_SELF']; ?>">
<table>
<tr><td>Username:
<td><input type="text" title="Enter your Username" name="txtUsername" />
<tr><td>Password:
<td><input type="password" title="Enter your password" name="txtPassword" />
<tr><td colspan=2 align=right><input type="submit" name="Submit" value="Login" />
</table>
</form>
<?php
}
else {


$_SESSION['logged_in'] == true;

echo "Hello ";
echo "$username";
echo ".<br>You will be redirected to the admin page in a couple of seconds...";

?>
<META http-equiv="refresh" content="2;URL=/admin/">
<?php
}
?>

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