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Reaper0167

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Posts posted by Reaper0167

    [SOLVED] password text boxes and initial values

    in PHP Coding Help

    Posted

    I forgot to mention that I am echoing out the form..... I'm getting an error....

    <?php
echo '<form name="form1" method="post" action="login.php">
			  <body onload="changeType()">
                  <input name="password" type="password" value="Password" id="password"
			        onfocus="if (this.value == "Password" && this.type == "text"){ this.value = ''; this.type = "password"; this.focus(); }" 
					onblur="if (this.value == '' && this.type == "password"){ this.value = "Password"; this.type = "text"; }" >
			  <input name="password" type="password" id="password" />
			  <input type="submit" name="submit" id="submit" value="Login"><br>
                  </form>';
?>

    [SOLVED] checkbox validation help

    in Javascript Help

    Posted

    my text field validation works,,  but check out the checkbox validation....What am I doing wrong?

    <script type="text/javascript" language="javascript">
    function validate(form2)
    {
    var valid = true;
<!--******************************************************************************************************************-->
    if (!form2.username.value || !form2.username_conf.value)
    {
        document.getElementById('username_error').innerHTML = 'You must enter a username and confirm it.';
        valid = false;
    }
    else if (form2.username.value != form2.username_conf.value)
    {
        document.getElementById('username_error').innerHTML = 'Usernames do not match.';
        valid = false;
    }
    else
    {
        document.getElementById('username_error').innerHTML = '';
    }
    
<!--***************************************************************************************************************-->	
if (!form2.password.value || !form2.password_conf.value)
    {
        document.getElementById('password_error').innerHTML = 'You must enter a password and confirm it.';
        valid = false;
    }
    else if (form2.password.value != form2.password_conf.value)
    {
        document.getElementById('password_error').innerHTML = 'Passwords do not match.';
        valid = false;
    }
    else
    {
        document.getElementById('password_error').innerHTML = '';
    }

<!--***************************************************************************************************************-->		

if (!form2.email.value || !form2.email_conf.value)
    {
        document.getElementById('email_error').innerHTML = 'You must enter a valid email and confirm it.';
        valid = false;
    }
    else if (form2.email.value != form2.email_conf.value)
    {
        document.getElementById('email_error').innerHTML = 'Emails do not match.';
        valid = false;
    }
    else
    {
        document.getElementById('email_error').innerHTML = '';
    }
<!--****************************************************************************************************************-->
if (!form2.agree.checked)
    {
        document.getElementById('agree_error').innerHTML = 'You must agree to the terms.';
        valid = false;
    }
    else
    {
        document.getElementById('email_error').innerHTML = '';
    }

return valid;
    }
</script>

    [SOLVED] password text boxes and initial values

    in PHP Coding Help

    Posted

    I am having a problem with a  text box on my site. The text box is where I enter in a password,, so when I type something,,, it is just a bunch of black dots.... How would I go about having the initial value of that text box say 'Password'  .. When I set the initial value to password,, it shows black dots,, only cause the type of the box is set to password.... What is the way around this?

    [SOLVED] little help please.

    in PHP Coding Help

    Posted

    Picture not displaying, little red x instead. Thought I had this one, guess not.

     

    <?php 
				  $imgRealPath = "userimages/";
				  foreach(glob("$imgRealPath/{*.jpg,*.png,*.gif}", GLOB_BRACE) as $fname)
				  {
				  	echo '<img src=\"" . $imgWebPath . "/" . baseName($fname) . "\" width="150" border="1"><br/><br/>'; 
				  }
?>

    echo an image from a directory on my hosting server

    in PHP Coding Help

    Posted

    header('Content-Type: image/png');

     

    I added this line to the top of the php page with the echo statment you showed me. But there is just a little red x.

     

    $newname="userimages/".$image_name;

    echo '<img src="$newname">';

     

    There is more code,, just showing what I am trying to echo.

    And is it possible to include png, jpg, and gif all in one header content?

    php mysql search engine

    in PHP Coding Help

    Posted

    i found this little bit of code

    <?php
<html> 
2 <head> 
3   <title>My page title</title> 
4 </head> 
5 <body> 
6 
7  <img height="125" width="125" alt="Flower" src="flower01.jpg" /> 
8 
9 </body> 
10</html>
?>

    Each picture will need a page like this, and then echo out the php page on my search results page????? How can this be done with all the images in the database?

    php mysql search engine

    in PHP Coding Help

    Posted

    by the way, this is not my script, i was just wondering how good it worked so I could get an idea of search engines. I tried the header code at the top of the page and all it shows is a little box with an x in the middle. And all the other content on the page was missing.

    <?php
header('Content-type:image/x-png');
include "upload_db_info.php";

  // Get the search variable from URL
  $var = @$_GET['q'] ;
  $trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$limit=10; 

// check for an empty string and display a message.
if ($trimmed == "")
  {
  echo "<p>Please enter a search...</p>";
  exit;
  }

// check for a search parameter
if (!isset($var))
  {
  echo "<p>We dont seem to have a search parameter!</p>";
  exit;
  }

//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("----","-----","-------"); //(host, username, password)

//specify database ** EDIT REQUIRED HERE **
mysql_select_db("-------") or die("Unable to select database"); //select which database we're using

// Build SQL Query  
$query = "select * from $table_name where name like \"%$trimmed%\"  
  order by name"; // EDIT HERE and specify your table and field names for the SQL query

$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);

// If we have no results, offer a google search as an alternative

if ($numrows == 0)
  {
  echo "<h4>Results</h4>";
  echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>";

// google
echo "<p><a href=\"http://www.google.com/search?q=" 
  . $trimmed . "\" target=\"_blank\" title=\"Look up 
  " . $trimmed . " on Google\">Click here</a> to try the 
  search on google</p>";
  }

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
  $query .= " limit $s,$limit";
  $result = mysql_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";

// begin to show results set
echo "Results";
$count = 1 + $s ;

// now you can display the results returned
  while ($row= mysql_fetch_array($result)) {
  $title = $row["content"];

  echo "$count.) $title" ;
  $count++ ;
  }

$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< 
  Prev 10</a>&nbsp ";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$limit) {
  // has remainder so add one page
  $pages++;
  }

// check to see if last page
  if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$limit;

  echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>";
  }

$a = $s + ($limit) ;
  if ($a > $numrows) { $a = $numrows ; }
  $b = $s + 1 ;
  echo "<p>Showing results $b to $a of $numrows</p>";
  
?>

    php mysql search engine

    in PHP Coding Help

    Posted

    php mysql search engine displays the blob image like this....what is going on?

    ‡ÿêB™\€„Àt‘8K€@zŽB¦@F€˜&S `ËcbãP-`'æÓ€ø™{[”! ‘ eˆDh;¬ÏVŠEX0fKÄ9Ø-0IWfH°·ÀÎ ² 0Qˆ…){`È##x„™FòW<ñ+®ç*x™²<¹$9E[-qWW.(ÎI+6aaš@.Ây™24àóÌ ‘àƒóýxήÎÎ6Ž¶_-ê¿ÿ"bbãþåÏ«p@át~Ñþ,/³€;€mþ¢%îh^  u÷‹f²@µ éÚWópø~<ß5°j>{‘-¨]cöK'XtÀâ÷ò»oÁÔ(€hƒáÏwÿï?ýG %€fI’q^D$.Tʳ?ÇD *°AôÁ,ÀÁÜÁ ü`6„B$ÄÂBB d€r`)¬‚B(†Í°*`/Ô@4ÀQh†“p.ÂU¸=púažÁ(¼ AÈa!ÚˆbŠX#Ž™…ø!ÁH‹$ ɈQ"K‘5H1RŠT UHò=r9‡\Fº‘;È2‚ü†¼G1”²Q=Ô µC¹¨7„F¢ Ðdt1š ›Ðr´=Œ6¡çЫhÚ>CÇ0Àè3Äl0.ÆÃB±8, “c˱"¬ «Æ°V¬»‰õcϱwEÀ 6wB aAHXLXNØH¨ $4Ú 7 „QÂ'"“¨K´&ºùÄb21‡XH,#Ö/{ˆCÄ7$‰C2'¹I±¤TÒÒFÒnR#é,©›4H#“ÉÚdk²9”, +È…ääÃä3ää!ò[ b@q¤øSâ(RÊjJåå4åe˜2AU£šRݨ¡T5ZB­¡¶R¯Q‡

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