Bman900
-
Posts
184 -
Joined
-
Last visited
Never
Posts posted by Bman900
-
-
Any one?
-
HAVING count(id) ... ? something missing there.
There we go!
$double = mysql_query("SELECT question, COUNT(id) AS cnt FROM question WHERE id IN(SELECT id FROM question GROUP BY question HAVING count(id) > 1)");I finally go something that makes sense but I only get one entry and I know there are more doubles and triples in my table.
My while statement is:
<?php while($row2 = mysql_fetch_assoc( $double )) { echo "<tr>"; echo "<td>".$row2['question']."</td>"; echo "<td>".$row2['cnt']."</td>"; echo "</tr>"; } ?> -
Ah this is frustrating, it got me a value but it is still not right.
I need to combine this:
$double = mysql_query("SELECT question FROM question GROUP BY question HAVING count(*) > 1") or die(mysql_error());with:
$double = mysql_query("SELECT COUNT(id) AS cnt FROM question WHERE id IN(SELECT id FROM question GROUP BY question HAVING count(id))");Please help me, am ripping my hair out here
-
Obviously you still need to select question in your query if you want the question as well.
I see what you mean now but I can't seem to do it right. So far I have:
$double = mysql_query("SELECT question AND COUNT(id) AS cnt FROM question WHERE id IN(SELECT id FROM question GROUP BY question HAVING count(id))");What am i doing wrong?
-
Well I am displaying my question, here is the code:
$double = mysql_query("SELECT COUNT(id) AS cnt FROM question WHERE id IN(SELECT id FROM question GROUP BY question HAVING count(id))"); ?> <table width="500" border="2" cellspacing="0" cellpadding="0"> <tr> <th>Name</th> <th>Number</th> </tr> <?php while($row2 = mysql_fetch_assoc( $double )) { echo "<tr>"; echo "<td>".$row2['question']."</td>"; echo "<td>".$row2['cnt']."</td>"; echo "</tr>"; } ?> </tr> </table>Or are you talking about the selecting it in my query?
-
I did that and got:
Question Number
10
-
Ok that looks like it might work but I need just a bit more help.
Here is the code I used to display the query I ran:
<table width="500" border="2" cellspacing="0" cellpadding="0"> <tr> <th>Question Asked 2 times</th> </tr> <?php while($row2 = mysql_fetch_assoc( $double )) { echo "<tr>"; echo "<td>".$row2['question']."</td>"; echo "</tr>"; } ?> </tr> </table>Obviously I need to make some changes to that but when I added
echo "<td>".$row2['id']."</td>";
But that didn't work. So how would I display this correctly?
-
Ok I got the following code to check for doubles:
$double = mysql_query("SELECT question FROM question GROUP BY question HAVING count(*) > 1")
or die(mysql_error());
Now is there a way to then display how many times those records are displayed in the database?
-
Well the thing is I wont be looking for a specific question, am just seeing if there are repeats and how many times it is repeated.
-
Is there a way to run a query that checks if a table has multipes of the samething and than print those out?
-
And for the questions, they are user inputed. So lets say user A asks: How was my day? and user B also asks: How was my day?
I want a report saying that How was my day? has been asked twice.
-
Well what if I do how many times a keyword has redirected to a page? could that be simpler?
-
Alright so I have a script that takes in questions and stores them into a database. What I want to do is have like a Most asked question's report. Basicly I want to look trough the databse and if there are two questions that are the same I want to print it in a table with a number next to it identifying how many times it apears.
Next I redirect the user based on keywords found in their questions which is also stored in the database. I then want to make a report on how many times each keyword apears in all of the questions in the databse.
Where would I even start on this complicated journey?
-
SELECT * FROM question WHERE id IN(SELECT id FROM question ORDER BY id DESC LIMIT 10) ORDER BY id ASC
But then I changed it to:
SELECT * FROM question ORDER BY [id] DESC LIMIT 10
which then worked.
-
Alright I solved it by making the code look like this:
echo "<tr>"; echo "<td>".$row['name']."</td>"; echo "<td>".$row['question']."</td>"; echo "<td>".$row['email']."</td>"; echo "</tr>";
But I get this: This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
I am running MySQL 5.0
-
Okay, so it sounds like you are pretty new to php, I would start by looking up basic queries to your database from the web using php in the reference section of the site. That will give you basic instructions on connecting to your database etc.
What you need to do is query your database to display a certain number of rows. What I would do in your situation is create two different php pages which query your database for ten rows, then for all of the rows in your table.
Thats exactly what I want to do.
Also Maq I see what you are doing but once I run it gives me an error like:
Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /homepages/44/d272374679/htdocs/draft/admin/report.php on line 102
Don't you have to like put a \ infront of <td> to escape the php for that second?
-
Alright two questions how do I make PHP create my table and then how would I flip the order if I do
SELECT * FROM question ORDER BY [id] DESC LIMIT 10
I don't want it to do 1-10 but rather 10-1.
-
I basically have a table in my database called 'question' with columns called 'name' 'question' 'email'
Than I have a table in my PHP page:
<table width="500" border="0" cellspacing="0" cellpadding="0"> <tr> <td>Question</td> <td>Name</td> <td>Email</td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> <tr> <td> </td> <td> </td> <td> </td> </tr> </table>
I want to show the last 10 question in my database along with email and names. Here is the code I have so far which just spits it out:
$result = mysql_query("SELECT * FROM question") or die(mysql_error()); while($row = mysql_fetch_assoc( $result )) { echo "Name: ".$row['name']; echo " Question: ".$row['question']; echo " Email: ".$row['email']; }Than I want to make another page that just spit every row out in a table like the first one but that automatically expands as more entries are added.
Where do I start?
-
I found it, I never included my variables for the original values. Wow am getting old or something...
-
Sorry about that, I will do it like that next time. I went back and did what you told me and got:
Array ( [titlecolor] => #00FF00 [headercolor] => #00FF00 [headerlinks] => #00FF00 [navbackround] => #00FF00 [navlinks] => #00FF00 [leftside] => #00FF00 [footercolor] => #00FF00 [footertext] => #00FF00 [sumbit] => Submit )
It looks like the error is with the update code, but everything matches up and it should give me an error if it doesnt. Any guesses?
-
Here is my code:
mysql_connect("$dbhost", "$dbusername", "$dbpassword") or die(mysql_error());
mysql_select_db("$databasename") or die(mysql_error());
$newtitlecolor = $_POST['titlecolor'];
$newheadercolor = $_POST['headercolor'];
$newheaderlink = $_POST['headerlinks'];
$newnavcolor = $_POST['navbackround'];
$newnavigationlink = $_POST['navlinks'];
$newleftsidecolor = $_POST['leftside'];
$newfootercolor = $_POST['footercolor'];
$newfootertext = $_POST['footertext'];
mysql_query("UPDATE style_options SET styleinput='$newheadercolor' WHERE styleinput='$headercolor' AND id = '1'")
or die(mysql_error());
mysql_query("UPDATE style_options SET styleinput='$newnavcolor' WHERE styleinput='$navcolor' AND id = '2'")
or die(mysql_error());
mysql_query("UPDATE style_options SET styleinput='$newleftsidecolor' WHERE styleinput='$leftsidecolor' AND id = '3'")
or die(mysql_error());
mysql_query("UPDATE style_options SET styleinput='$newfootercolor' WHERE styleinput='$footercolor' AND id = '4'")
or die(mysql_error());
mysql_query("UPDATE style_options SET styleinput='$newheaderlink' WHERE styleinput='$headerlink' AND id = '5'")
or die(mysql_error());
mysql_query("UPDATE style_options SET styleinput='$newnavigationlink' WHERE styleinput='$navigationlink' AND id = '6'")
or die(mysql_error());
mysql_query("UPDATE style_options SET styleinput='$newfootertext' WHERE styleinput='$footertext' AND id = '7'")
or die(mysql_error());
mysql_query("UPDATE style_options SET styleinput='$newtitlecolor' WHERE styleinput='$titlecolor' AND id = '8'")
or die(mysql_error());
echo "Update succesfull!<br />";
echo "<center>[<a href=\"editstyle.php\">Go BACK</a>]</center>";
The Update successful message comes trough but nothing really gets updated. Whats wrong here?
-
PERFECT! Thank you!
-
Well I want to make it simple for the user. Basically this is what I want to do:
.css file
#header {
color: #003399;
background: #8CA8E6;
}
And then my admin panel would have:
Backround: ___________ SUBMIT
Can this be done in .css?
<?php $backround = "#8CA8E6"; ?>
#header {
color: #003399;
background: <?php echo"$backround"; ?>;
}
-
Basicly I have an admin panel where I want to edit certain colors in a .css file. Can I include PHP in the .css to make this work?
User lock out after 5 failed tries
in PHP Coding Help
Posted
Alright so I used a pre made script for a secure log in for my admin panel but I want to add a few more security things to it. Basically I want to make it if a user get his or her password wrong 5 times the account will be locked and and email will be dispatched with a new password.
Here is part of the code where the log in errors are handled:
function procLogin(){ global $session, $form; /* Login attempt */ $retval = $session->login($_POST['user'], $_POST['pass'], isset($_POST['remember'])); /* Login successful */ if($retval){ header("Location: admin/admin.php"); } /* Login failed */ else{ $_SESSION['value_array'] = $_POST; $_SESSION['error_array'] = $form->getErrorArray(); header("Location: adminlogin.php"); } }