mraza

hi i need to get value after Multiplication in a loop as total, plz how can i do that here is my code while ($row = mysql_fetch_array($name)) {?> <td><?php echo $row['service']; ?></td> <td><?php echo $result['qty'] ; ?></td> <td><?php echo $total = ($result['qty'] * $row['price']); ?></td> <?php } ?> i need to get $total of sum after loop, currently it shows only individual.. thanks for any help.. Regards

Thank you very much sir for your help. its solved

hi i am in situation to display input box along with select option , here is my code <?php $run= $dbc->db("SELECT * FROM `table` WHERE `id`='$id'"); ?> <select name="service"> <?php while ($result = mysql_fetch_array($run)) { ?> <option value="<?php echo $result['id'] ; ?>"><?php echo $result['service'] ; ?></option> <?php // This is problem i need to get this as hidden field but it breaks my select options. ?> <input type="hidden" value="<?php echo $result['data'] ; ?>" name="data" /> <?php } ?> </select> so here i am stuck <input type="hidden" value="<?php echo $result['id'] ; ?>" name="data" /> when i repeat in while loop it breaks options box and display other options without in select box. any help please thanks

hi i am working on a php form where i need to get user signature and store in a db or as file, here is a link to an applet with perl but i am not sure about it. i need something like this http://www.lawrencegoetz.com/programs/signature/ Please can anyone tell if there is something related for php. thanks for any suggestion.

hi i need a little help with javascript, I have one drop downl list which is populating from mysql <script type="text/javascript"> function show() { // dont know what to put here :-\ } <script> <select name="user" onchange="show()"> <option value="0">Select a user </option> <option value="1">First Name of one user </option> <option value="2">First Name of second user</option> <option value="3">First Name of third user</option> </select> <input type="text name="fname" value="" /> Now what i wants is when i change first option to second it will fill value="" of input box with that user second name which i need to run mysql query but i am not good with javascript so really appreciate for any help. Thanks

Thanks Alex for the help

Hi i am in a situation where i need to use two tables. please look at my code $result= $db->dbrun('select * from table_user'); while($row = mysql_fetch_array($result)): echo $row['username'] . '<br />'; endwhile; now my problem is i wants to get something from other table where user id match with $row['id'], $result= $db->dbrun('select * from table_user'); while($row = mysql_fetch_array($result)): $query= $db->dbrun('select id from table_other where user_id =$row['id']'); while($user_row = mysql_fetch_array($query)): echo $row['username'] . ' - ' . $user_row['id'] . '<br />'; endwhile; endwhile; so my main question is is it ok to run $query within a while loop because i cant run this query without $row['id'] which i gets after loop started or is there any other good way. Thanks for answering.

Thank you Ken that looks perfect

i dont know if i was good but i make it work with it, function FileExtension($filename) { $mp4 = "mp4"; $flv ="flv"; $avi = "avi"; $gp = "3gp"; $mpeg = "mpeg"; $flvcheck = $filename.".".$flv; $mp4check = $filename.".".$mp4; $avicheck = $filename.".".$avi; $gpcheck = $filename.".".$gp; $mpegcheck = $filename.".".$mpeg; echo $test; if (file_exists($flvcheck)) { $extension = $flv; } elseif (file_exists($mp4check)) { $extension = $mp4; } elseif (file_exists($avicheck)) { $extension = $avi; } elseif (file_exists($mpegcheck)) { $extension = $mpeg; } else { $extension = $flv; } echo $extension; } If there was some more fency way plz let me know Thx

Hi i wants to know how can i get a file name extension in directory, for example file name is "thisfile" and there could be any of these thisfile.txt or thisfile.pdf or thisfile.doc in current directory , but there is only one file with that name in directory either with txt or pdf or doc extension, and i need to get that file name extension , please can someone help how can i know the extension of "thisfile" using php. thanks

sorry it was php related question, nvm i figured it out here solution preg_match("/(?s)img\.src = '(.*?)';/", $html, $m1); Thanks

Hi i wants to extract a link from a script line i wants to get this line img.src = 'http:\/\/this link i wants to extract'; from below code, please can someone tell me how can i do that. <script> var yt = yt || {}; t.preload = {}; y.preload.start = function() { var img = new Image(); t.preload.videoConnection = img; img.onload = img.onerror = function () { delete t.preload.videoConnection; }; img.src = 'http:\/\/this link i wants to extract it alos contain $%&= type of words'; img = null; }; yt.preload.start(); </script> Thanks for support

Thanks for qucik help but i get this error Fatal error: Call to undefined function http_parse_message() in /home/admin/mysite.com/test2.php on line 4 my code <?php error_reporting(E_ALL); ini_set("display_errors", 1); print_r(http_parse_message(http_get('http://www.site.com'))->headers); ?> i guess need to compile something , is not there any other way that does not include any server configuration? Thanks

Hi i wants to know how i can get headers to display on page, for example if i visit to www.thissite.com i see in headers with livehttpheaders it is also showing some more URL's and keep refreshing even i am on that page like www.pic.thissite.com video.thissite.com css.thissite.com So i wants to extract that URL's from headers with curl. Please any support. Thanks

you can add one date column in your replies table, and sort them by date

sorry but i am not clear what you are trying to say, last script i assumed you have one file named "textfile.txt" within same location you are running this script , you wants to read that file and find some words and replace them, if so that should work, other then not clear to me

you can use global server variable $_SERVER['document_root'] and then add your file location i guess.

<?php $file = 'textfile.txt'; if (file_exists($file)) { $ff = fopen($file, 'r+'); $contents = file_get_contents($file, FILE_TEXT); $change= array("My name is", "Hi", "Come back"); $replace = array("is name my","Hello","I coming"); $new_contents = str_replace($change, $replace, $contents); file_put_contents($file, $new_contents, FILE_TEXT); fclose($ff); $ff = fopen($file, 'r+'); fwrite($ff, $new_contents); fclose($ff); } else { echo "The file $filename does not exist"; } ?> something like this?

<?php $values = 8; for($i = 1; $i <= $values; $i++) { echo $i . ':'; if($i == 1) { echo $i * 0; } else { echo ($i * 50) - 50; } echo '<br />'; } ?>

not clear, can you show your image code? if you are looking for image width then why not try to set in img tag? like <img src="" width="" height="" />

<?php $value = 8; for($i = 1; $i <= $values; $i++) { echo $i . ':'; echo $i * 50; echo '<br />'; } ?> hope this what u wants

Thanks for help here i find one more http://www.phptutorial.info/iptocountry/the_script.html cheers

hi ! i wants to make a script which would be country based, lets say if visitor ip on my site is from UK he will see echo "you are coming from UK !"; if visitor is from US he will see echo "you are coming from US !"; if he is from other country they will see that message i will write for them, so is there any open source available? or any idea how can i complete this task, Thanks for help

hi i am trying to run a script with zend code nut not working, in my phpinfo(); it display ; This program makes use of the Zend Scripting Language Engine: Zend Engine v2.2.0, Copyright © 1998-2008 Zend Technologies with the ionCube PHP Loader v3.1.31, Copyright © 2002-2007, by ionCube Ltd., and with Zend Extension Manager v1.2.0, Copyright © 2003-2007, by Zend Technologies with Zend Optimizer v3.2.8, Copyright © 1998-2007, by Zend Technologies and Zend Optimizer Optimization Pass 1 enabled Optimization Pass 2 enabled Optimization Pass 3 enabled Optimization Pass 4 enabled Optimization Pass 9 enabled Zend Loader enabled License Path no value Obfuscation level 3 i am using PHP Version 5.2.11 ,when i do the test it shows me zend optimizer is not installed, i am using centos 5 wtih kloxo /apache. , i also found this tutorial and there are some files i tried but not working http://en.ispdoc.com/index.php/Installing_Zend_Optimizer thanks for any help

ok thx for help all is done i need to fix css