Alex

You're getting that error because mysql_query is returning boolean false as a result of your query failing. You need to use quotes, not back ticks. $login = sprintf("SELECT * FROM user WHERE username='%s' AND password = '%s'", mysql_real_escape_string($post_username), mysql_real_escape_string($post_password));

Your code could look something like: $con = mysql_connect("","",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_database", $con); require_once('recaptchalib.php'); $privatekey = "private_key"; $resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); if (!$resp->is_valid) { // What happens when the CAPTCHA was entered incorrectly die ("The reCAPTCHA wasn't entered correctly. Go back and try it again."); } else { if(empty($_POST['quotes'])) { // Tell them they missed a required field } else { $sql="INSERT INTO pendingquotes (quotes, email, name) VALUES ('$_POST[quotes]','$_POST[email]','$_POST[name]')"; mysql_query($sql,$con); echo 'Thanks for your submission '; mysql_close($con); } }

fputcsv is a built in PHP function, you can't declare a function of that name.

You can validate your input with a function like empty and not submit it to the database if it is empty. For more specific help we'll need to see relevant code.

You must have output somewhere else before you're doing this. The hash you should get is: e85ea73176c48d8723fb18211c4a9499 Which is in the string you're getting: lujxikk46nx7l2m94e85ea73176c48d8723fb18211c4a9499. The first part must be coming from somewhere else.

I think you mean OR instead of AND.

Take a look at imagegrabwindow.

What version of PHP are you running (you can check this by using phpinfo)?. As you can see from the manual on sha1() it requires PHP 4.3.0+.

Put curly braces around $_POST['text'] when you're echoing it in that string of text. And by the way, is_int($_POST['times']) will never be true. Variables in the $_POST array will always be strings and not integers, instead you should use is_numeric.

That's referring to this in the for loop: $i >= $_POST['times']

Your script is relying on register_globals. You should instead be accessing the data from the $_POST array. So $times becomes $_POST['times']. Additionally you have a flaw with your logic, the comparison operator you should be using is < not >=. if(isset($_POST['submit'])){ for($i=0; $i < $_POST['times']; $i++){ echo $_POST['text']; echo '<br />'; }

You need to put quotes around data that isn't being inserted into a numeric typed column. mysql_query("INSERT INTO subscriptions (email, confirmation number, verified) VALUES ('$email', $confirmation_number, 'no')") or die('Error'); Depending on the data type, you might need to put quotes around $confirmation_number as well, because the variable name is $confirmation_number I assumed it's being inserted into a column with a numeric data type.

$img = imagecreatefromjpeg("image2.jpg"); $rgb = imagecolorat($img, $x, $y); // replace $x and $y here to be the point you want.. imagecolorset($img, $rgb, 0, 0, 255); header('Content-type: image/jpeg'); imagejpeg($img, 'simpleimg.jpg');

It should work as long as you're inputting the correct information. The script should look something like this: $img = imagecreatefromjpeg("image2.jpg"); $rgb = imagecolorat($img, $x, $y); // replace $x and $y here to be the point you want.. imagecolorset($img, $rgb, 0, 0, 255); header('Content-type: image/jpeg'); imagejpeg($img); That would take image2.jpg and take whatever color is at point ($x, $y) and replace it throughout the whole image with blue, and then display it in the browser.

Did you change the $x and $y to the x and y of the pixel containing the color that you want to replace?

That code will loop through every color and change that color to blue. Making the entire image blue. Try something like: $img = imagecreatefromjpeg("image2.jpg"); $rgb = imagecolorat($img, $x, $y); // replace $x and $y here to be the point you want.. imagecolorset($img, $rgb, 0, 0, 255); You're also not outputting the new image to see the changes. Add this to the end of the script: header('Content-type: image/jpeg'); imagejpeg($img); imagejpeg

To go two folders up you would do ../../. If you want more specific help you'll need to post the relevant code.

Oh sorry, I thought you meant other columns.. To loop through all the rows returned you can do this (you were already provided with this in another topic..): while($row = mysql_fetch_assoc($result)) { echo $row['id']. " - ". $row['quotes'] . "<br />"; }

What do you mean? I don't see an argument for changing the quality :/ EDIT: nevermind found it, but it requires you to save the file. I don't need to save the file. That's not true: You simply pass null as the second parameter, something like this: imagepng($im, null, 0);

echo $row['row name']; But you need to make sure you add it to your select query as well.

The function is get_class_vars not get_class_variables(), but this won't work for what you're looking for. This gets the default values for a class given the name of the class, not an instance of the class. Instead use get_object_vars.

Using the image*() function (depending on your format, png, jpeg, etc.. whichever one you're using) you can specify the quality of the image. Trying increases the quality.

Ah, if the data is ordered that way then yeah, that's a better solution.

You forgot to take into account that he wants the largest day value to be used if multiple exist.

From the sounds of your problem it definitely seems like it can and should be solved through MySQL. You can try: SELECT name, MAX(days) as max_days FROM table GROUP BY name In the case that I'm misunderstanding and this really can't be achieved through MySQL here's a PHP solution: $arr = array( array( 'name' => 'george', 'days' => 20 ), array( 'name' => 'george', 'days' => 10 ), array( 'name' => 'nickie', 'days' => 20 ) ); function getNameIndex($arr, $name) { foreach($arr as $key => $val) { if($val['name'] == $name) { return $key; } } return false; } $new = array(); foreach($arr as $key => $val) { if(($index = getNameIndex($new, $val['name'])) !== false) { if($new[$index]['days'] < $val['days']) { $new[$index]['days'] = $val['days']; } } else { $new[] = $val; } } echo "<pre>" . print_r($new, true) . "</pre>"; Output: Array ( [0] => Array ( [name] => george [days] => 20 ) [1] => Array ( [name] => nickie [days] => 20 ) )