[user profile url help]

nvm i found a solution...basically i want a "pretty" url. thanks for the help anyway

[user profile url help]

ok how do i get the page to display? i get this error

 

Not Found

 

The requested URL /test was not found on this server.

 

for example the url is this

http://www.example.com/$username

[user profile url help]

if you are talking about the actual text after http://www.example.com/Username,

you can use a regular expression to match the text.

$pattern = '/^http\:\/\/www\.[a-zA-Z0-9]+?\.com\/([a-zA-Z-0-9]+?)/';

 

so $pattern will get the Username from the url?

[user profile url help]

How do i use GET to get the username if the url is like this

 

http://www.example.com/Username

 

or is there another method rather than GET?

[Parse error disappears when refreshing page?]

at random times i get a parse error unexpected $end on a random line.  Then i refresh the page and everything is working.

 

Does anyone have an idea on why this error is inconsistent? 

 

It's hard to debug because i don't know when it's going to show up, completely random.  I have matched brackets and checked semicolons.  i would comment out code but like i said it's random.  If refreshing the page makes everything work, what could be the culprit?

[Warning: Cannot modify header information - headers already sent ..]

ok i don't understand.

 

 

this is the line that causes it

 

 header( 'Location: ' . $return );

 

 

The solution is to determine what that output is and prevent it from occurring before you attempt to do a header() redirect.

 

$return is the url of the current page, so when logging out it reloads current page.

 

What do i have to prevent?  I have a session_start(); at the top of the page is that what is causing it?

[Warning: Cannot modify header information - headers already sent ..]

i get the error "Warning: Cannot modify header information - headers already sent by" with the below code. How do i solve it without using output buffering?

 

function logout($return) {

	unset($_SESSION['admin']);
	unset($_SESSION['username']);
  header( 'Location: ' . $return );
echo "<div class='fontall'><span class='fontdif'>You've been logged out.  </span><a href='$return'>Click Here</a><span class='fontdif' to return</span></div>";

	}

[wordwrap problem]

thanks for the replies but do you know why i get the error? it should be a full <br /> tag instead of <br..

 

 

[wordwrap problem]

When i check the source code I get this error

 

rotator cuff<br />strengthenin<br..

 

you can see the br tag is cutt off.  The code is below.

 

$thename = "rotator cuff strengthening";

 

	$newname = wordwrap($thename, 12, "<br />", true);

$limit = 33;

	if (strlen($newname) > $limit)
	{ 
		 $newname2 = substr($newname, 0, $limit) . '..'; 

	 }
		 else
	{
		$newname2 = $newname;

	}			

[str_replace with form help]

With this form... if i typed in "new test" in the search text field the url would come up as

 

test.php?search=new+test

 

How do i get the url to replace spaces as a dash instead of a plus sign?

 

<form action="test.php" method="GET" name="searchbar">

		<?php 


	$search = strtolower($_GET['search']);

	$formpage = $_SERVER['PHP_SELF'];

echo "<input type='text' size='40' name='search' style='font-size:16px; font-family:Arial;font-weight:bold;' />  <input type='submit'  value='Search' style='font-size:14px;' />";

		?>

			</div>

	</form>

[update query not working]

thanks it works.  learned something new. 

[update query not working]

this query isn't working.

 

foreach($rating as $value) //foreach loop which updates totalsum every array key
		{

			if($value>0) {
			$totalsum = mysql_query("UPDATE block SET totalsum=totalsum+$value WHERE id=$d",$this->connect);
			}
		}

 

i echoed the query and get this

 

UPDATE block SET totalsum=totalsum+2 WHERE id=16 AND id=17 AND id=18 AND id=19

 

it should work. I have entries in mysql with those id's. It should update the totalsum column by 2 for those id's

[Parse error: syntax error, unexpected $end]

i get this error randomly appear  Parse error: syntax error, unexpected ..... on line 3094

 

line 3094 is

function account($username,$email,$password,$cpassword) {

 

this appears randomly... if i refresh the page, everything works..  Any idea what is the problem?

[body onload not working]

nvm

[get current array key help]

$_SESSION[$c] is an array in a loop.  How do i do an if statement that gets the current array key?

 

if($_SESSION[$c][]==$_SESSION[$c][1]) {


}

i tried the above but i get this error "Fatal error: Cannot use [] for reading in..."

[if end of array in loop help]

nvm.. i got the solution

 

end($array);
$lastKey = key($array);

[if end of array in loop help]

$_SESSION['people'] is an array.  I add to $_SESSION['people'] by doing this...

$_SESSION['people'][] = $people;

 

basically how do i code "if last key in array?"..

 

i tried this but it's not correct

 if(end($_SESSION['people'])) {
    //code

    }

[if end of array in loop help]

How do i do if i've reached of array?  i know i could do end of loop.  but the array is present many times in my code.

 

while($row = mysql_fetch_assoc($getdetails)) {
$people = $row['people'];
$_SESSION['people'][] = $people;

    if(end($_SESSION['people'])) {
    //code

    }
}

[help with div show and hide]

i want the div to start off hidden.  I know how to make it show and hide.  The problem is when i load the page the border is seen. If i use display:none; in the div css the div doesn't display even when i press the button with the function to show.

 

open and close function

function infobox(number) {
document.getElementById('userinfo').style.display = "block"; //displays userinfo
  
}

function closeinfo() {
document.getElementById('userinfo').style.display = "none";

}

 

div css

#userinfo {
position:absolute;
text-align:left;
width:900px;
height:auto;
top:100px;
left:50%;
font-size:14px; 
font-family:Arial;
z-index:20;
margin-left:-450px;
background-color:#FFFFFF;
border:1px solid #264971;

}

[implode error help]

nvm i fixed it... thx anyway

[implode error help]

i put values in the array like this

 

$_SESSION[$v][] = "<div class='informationtop'></div>
		<div class='informationmiddle'><p>Added by <b>$theuser</b></p><p>$name</p><p>$reason</p></div>
		<div class='informationbottom'></div>";

 

if i print_r($_SESSION[1]);  the array has the correct values.  but for some reason the error is showing up.

[implode error help]

yes i've tested it is an array.  Still coming up with the error 9 times, each on the same line with the implode.

[implode error help]

i keep on getting this error..  Warning: implode() [function.implode]: Invalid arguments passed in...

 

$rowinformation is an array, i don't see where the problem is.

 

	for($v=1;$v<11;$v++) {
	$rowinformation = $_SESSION[$v];
	echo "<div style='display:none;' id='$v'>".implode("<p> </p>",$rowinformation)."</div>"; // outcome string information

	}

[div content adding on.. not being replaced]

nvm

[display mediumblob image help]

it's not displaying the image... any help?

 

echo "<img src='advertimage.php?id=$advertid' />"; 

 

advertimage.php

<?php

$id= $_GET['id'];

$thedatabase = new Database2();
$thedatabase->opendb2();

$advert = $thedatabase->viewadvert($id);
header("Content-type: image/jpeg");
  echo $advert;
$thedatabase->closedb2();

?> 

 

 

viewadvert function

function viewadvert($id){
$getadvert = mysql_query("SELECT * FROM `advertise` WHERE `id`='$id' LIMIT 1",$this->connect);

$row=mysql_fetch_assoc($getadvert);

$image = $row['image'];

return $image;

}