awjudd

It didn't help because you didn't copy it correctly. Please re-read my previous post and you'll see the differences. ~juddster

Anywhere before you actually try to use $ca_id. ~juddster

$_SESSION['username'] = $username; You are overwriting your previous value with an empty string. ~juddster

No the server is not up and running, no the server isn't running on port 3406, or no phpmyadmin isn't working? Or no something entirely different? ~juddster

You need to provide mysqli_query the connection object that you get from mysqli_connect because of this the other errors are showing up. ~juddster

Is your mysql server up and running on port 3406? If yes, have you updated the phpmyadmin configuration file accordingly? ~juddster

What port is your MySQL server running on? Is this the port that you tell phpmyadmin? ~juddster

Both servers cannot run connected to the same port. Either the server you stopped failed to start up again, or you didn't restart the server after adjusting the configuration. ~juddster

$cfg['Servers'][$i]['port'] = '90'; That should be your MySQL server port not your web server port. ~juddster

Just before the auto submit is done trigger the click event for the other thing? ~juddster

There should be a configuration file for phpmyadmin somewhere (http://webmaster.iu.edu/tool_guide_info/phpmyadmin/phpmyadmin.shtml). Make sure that is using the correct port for your MySQL server (http://www.coderanch.com/t/298301/JDBC/java/which-port-mySQL-running) ~juddster

No ... registered_globals was deprecated and turned off by default for a reason. Your code should handle it, not assume the server will. ~juddster

It looks like you might have been previously using registered_globals. I don't see anywhere in your code where you set the variable $ca_id. You are going to need to adjust the code so that it does grab that value. $ca_id = $_GET['ca_id']; My guess is that your old host had it enabled but your new one does not. ~juddster

Sorry for wrong link .. skimmed through it and thought it mentioned the server's port. As for the server's port, is MySQL server running on it's default port or a different one? ~juddster

Has the server's port changed? http://veerasundar.com/blog/2009/01/how-to-change-the-root-password-for-mysql-in-xampp/ ~juddster

I believe that this is a PHP issue and not a MySQL one. Can you please provide some code where it isn't working? ~juddster

PHP is server side, jQuery is client side. There is no way to directly use the PHP variables in JavaScript. Indirectly, you could do something like this: <script type="text/javascript"> var foo = "<?php echo $superSpecialVariable; ?>"; </script> To assign client-side variables at run time. ~juddster

If your mysql server running? ~juddster

I would try to remove the requirement of the main page being reloaded in order for the sidebar to work properly. Maybe you can extract it out into another php file which they can require? ~juddster

Are you trying to use PHP values in your JavaScript call? If yes, then you don't have access to them since JavaScript is all client-side. Your best bet would be to assign the values of your PHP variables to values in your JavaScript. <script type="text/javascript"> var foo = "<?php echo $superSpecialVariable; ?>"; </script> Or I completely misread your post ... ~juddster

Then yes, use the session variable. You shouldn't hit the database with queries if not necessary ~juddster

If you are using database parameters for your query there is no need to escape them. Or if you aren't you would do something like what you have at the bottom. ~juddster

You shouldn't be using htmlentities to prevent SQL injection. There are other functions to do that for you (i.e. mysql_real_escape_string) or better yet, use database parameters. ~juddster

If you already have the username in a variable (i.e. $username) then why are you querying the database for it? ~juddster

Either you can build an array of all of the errors and output it like you have it the first way, or just echo it as you go to get the output like you have the second way. <?php if (isset($_POST["Submit"])) { $arrLines = split(",",$_POST['cellphonenumber']); $errors = array (); foreach($arrLines as $cells) { if(!preg_match('/^[0]{1}[1]{1}[0-9]{1}[0-9]{7}?$/', $cells)) { $errors [] = $cells; } } } if ( count ( $errors ) == 0 ) { echo 'All Successful'; } else { foreach ( $errors as $error ) { echo $error; } echo ' is not a valid number.'; } ?> <form action="" name="myform" method="post"> <textarea name="cellphonenumber" rows="20" cols="100"></textarea> <input type="submit" name="Submit" /> </form> ~juddster