include

[alin19]

how can i declare a var in a php file and to be used in a second file that is included in first?

 

i know that i haven't been very clear with this, so i have an example here:

 

 

<?php

$x="test";

include ("/usingtest.php");

?>

 

 

//usingtest.php

<?php

 

$y=$x

 

?>

[wrathican]

as far as i know you need to declare the variable in the included file:

<?php
//setx.php

$x = "test";
?>

<?php
//displayx.php

include ('setx.php');

$y = $x;

echo $y;

?>

 

woud output:

 

test

[micah1701]

when you include a file, its just like copying and pasting the code from that other file into the parent file so, what you're proposing should work fine.

 

<?php //page2.php
$y = $x + 3; 
?>

 

<?php //parent page
$x = 2;
include('page2.php');
echo $x * $y; // result: 10

?>

[alin19]

but i need the other way around, what can i do than?

 

i need a var declared in the first file to could be included in the second one;

 

//first

<?php

<form>

<input type=text name="form">

</form>

$x=$_POST['form'];

include(second.php);

?>

 

 

//second

<?php

echo "test";  //this isn't working

 

$y=$x;

echo $y;  //and this also isn't working

?>

 

 

 

 

[micah1701]

are you sure you have the path to the include file right?

 

echo "test";  should at least print the word test  ???

 

as a test, try using require() instead of include()

 

if the path is wrong, the parent page will throw an error (or not load at all)