[SOLVED] check if already posted..

[abs0lut]

i don't want to display the input form if he already posted once..

how to check if he already posted?

[dezkit]

if($user = uses_details_in_thread){

echo "there might be a chance of getting a correct answer";

}

[DarkWater]

I lol'd. D:

[Fadion]

loool.

 

Set a session/cookie when the user posts the form and use it to check if he already posted. It could be bypassed but theres no other good way.

[abs0lut]

loool.

 

Set a session/cookie when the user posts the form and use it to check if he already posted. It could be bypassed but theres no other good way.

do I need to store the session in database??

when I logout, and I login again,  the form appeared ...

 

[Fadion]

If u have a user based site, u can save the "already_posted" as a database field. If not u can only count on pure sessions and cookies which can be deleted. You are most surely destroying all your session variables when logging out, thats why the form appears again. A cookie would be more appropriate in this case, but they can be always deleted.

[abs0lut]

echo "<input type=\"text\" name=\"cost[]\" /><br>";

for ($i=0; $i<count($niqid); $i++) {

 

    $query = "INSERT INTO ctable (userid, name, cost, total, date, postid)

              VALUES ('$userid', '".$niqid[$i]."', '".$cost[$i]."', '$total', '$date', '$post')";

    $sql = mysql_query($query) or die (mysql_error());

}

I want the input form cost to disappear if he posted already. please help me..