[SOLVED] grabbing a users image

[runnerjp]

for some reason when and try and get the users image via

 

$getuser="SELECT * FROM users WHERE Username = ".$gettopic3['author']." "; 


$getuser2=mysql_query($getuser) or die("Could not get user");

while($getuser3=mysql_fetch_array($getuser2)){

  $getthreads3['image']=strip_tags($getthreads3['image']);
  echo $$getthreads3['image'];

 

i echo the query and it worked fine SELECT * FROM users WHERE Username = Admin

 

 

the full code is below

 

<table class='maintable'>

<tr class='headline'><td width=20%>Author</td><td width=80%>Post</td></tr> <?php
if ($pagenum == 1){
?>
<tr class='mainrow'><td valign='top'><?php echo $gettopic3['author'] ;

$getuser="SELECT * FROM users WHERE Username = ".$gettopic3['author']." "; 


$getuser2=mysql_query($getuser) or die("Could not get user");

while($getuser3=mysql_fetch_array($getuser2)){

  $getthreads3['image']=strip_tags($getthreads3['image']);
  echo $$getthreads3['image'];
  }

?>
</td>
<td vakign='top'>created on <?php  echo $gettopic3['showtime']?><br>
  <hr>
  <p>
  <?php

$message=$gettopic3['post'];

$message=nl2br($message); ?>

  <?php echo $message ?></p>
  <p><br>

    </p></td></tr>
<?php
}

$getreplies="Select * from forumtutorial_posts where parentid='$id' $max"; //getting replies

$getreplies2=mysql_query($getreplies) or die(mysql_error()."Could not get replies");

while($getreplies3=mysql_fetch_array($getreplies2))

{

   ?><tr class='mainrow'><td valign='top'><?php echo $getreplies3['author']?> </td><td vakign='top'>replied  at <?php echo $getreplies3['showtime']?> <br>
  <hr>
    <p>
      <?php

   $message=$getreplies3['post'];

   $message=nl2br($message);

   ?>
      <?php echo $message?></p>
    <p><br>

      </p></td></tr>
<?
}
?>
</table>

[jonsjava]

forgot single quotes:

$getuser="SELECT * FROM users WHERE Username = '".$gettopic3['author']."' "; 

[runnerjp]

oh boy that waa an easy 1 lol... sorry just learn today about the doubble n single quotes thing lol

[runnerjp]

ok i have a quote issue again in my link

 

echo "<img src=\"http://www.runningprofiles.com/images/$getuser3['image']\" border=\"0\"  />";

 

im styill not quite sure how to do $getuser3['image']

[jonsjava]

safest bet:

<?php
$image = $getuser3['image'];
echo "<img src=\"http://www.runningprofiles.com/images/$image\" border=\"0\"  />";

[peranha]

should be

 

echo "<img src=\"http://www.runningprofiles.com/images/$getuser3[image]\" border=\"0\"  />";

 

without the ' quotes in the url

[DarkWater]

ALL arrays need to be enclosed in { } to be used in double quotes.