[SOLVED] preg / str_replace

[Schlo_50]

Hi guys,

 

I have 6 variables which need to be placed into a string, each separated by commas. I can do that, BUT, sometimes not all of the variables will have a value so when I print my string I get something like the following:

 

var1, var2, , var4, var5, var6

 

I have tried to use str_replace to get a nice comma separated list without a comma at the end of the last number but it's not really working well. Has anybody got any ideas as to how I can code this please? My example code follows:

 

$relevant = "1a";
$relevant_two = "2b";
$relevant_three = "3c";
$relevant_four = "";
$relevant_five = "5e";
$relevant_six = "6f";

$strt_string = "$relevanta, $relevantb, $relevantc, $relevantd, $relevante, $relevantf";

$srt_string = str_replace(' ,', '', $strt_string);

 

Thanks in advance!

[DarkWater]

Put them all in an array and do:

 

foreach ($relevant as $v) {

  if (!is_null($v)) {

  $strt_string .= $v;

  }

}

[samshel]

Simplest way

 

$arrString = array();
$arrString[] = "1a";
$arrString[] = "2b";
$arrString[] = "3c";
$arrString[] = "";
$arrString[] = "5e";
$arrString[] = "6f";

$strString = implode(",", $arrString);

 

 

 

[Schlo_50]

Thanks