preg match

[Nandini]

Hi all

 

This is very good forum. I got so much solutions from this. I thank to all.

ok my problem is

i have a string like 111:111111@192.168.121.111:5080/111

 

I want to know  "/" is there in my string or not. I have to write some script if "/" is there in that string.

So can any one give me preg_match to find that "/".

 

Thanq

[JasonLewis]

Just use strpos().

 

$str = "111:111111@192.168.121.111:5080/111";

if(strpos("/", $str)){
echo "It's in there!";
}else{
echo "Couldn't find it!";
}

[DarkWater]

Actually, that's not how you are supposed to use strpos, ProjectFear.  You need to do something like:

 

$str = "111:111111@192.168.121.111:5080/111";

if(strpos("/", $str) !== FALSE){
echo "It's in there!";
}else{
echo "Couldn't find it!";
}

 

That's because if the character appears at the first position in the string, strpos() returns 0, and not FALSE, but it's still evaluated as FALSE unless you explicitly say otherwise.

[nrg_alpha]

I think I would side with the function strpbrk:

 

$str = "111:111111@192.168.121.111:5080/111";
if(strpbrk($str, '/') == true){
   echo "It's in there!";
} else {
   echo "Couldn't find it!";
}

[JasonLewis]

Actually, that's not how you are supposed to use strpos, ProjectFear. You need to do something like:

 

$str = "111:111111@192.168.121.111:5080/111";

if(strpos("/", $str) !== FALSE){
echo "It's in there!";
}else{
echo "Couldn't find it!";
}

 

That's because if the character appears at the first position in the string, strpos() returns 0, and not FALSE, but it's still evaluated as FALSE unless you explicitly say otherwise.

 

Yeah if I took the time to look at the big red headings in the manual that say "WARNING". Thanks for the correction.

Cheers.