Jump to content

[SOLVED] Is this possible ?


Rommeo

Recommended Posts

Hi

As I am a newbie, there is something that i dont understand.

My question is :

 

i have a mysql table which keeps the data of the pages like "about us" & "contact" etc.

for to enter contact, i type :

"www.mywebsite.com/page.php?id=contact" 

 

and i have a page which looks for the data by the while loop named ad "photos.php"

for to see photos, i type

"www.mywebsite.com/photos.php"

 

And my question is ..

What if i write the "while-loop-code" in my mysql table, would it work ? when i enter ;

"www.mywebsite.com/page.php?id=photos"

 

As i said my photos.php file is just a mysql query which shows all the photos. I wanna save that code in my mysql.. But i m not sure whether that works. Is it possible ? Is there anyway to do that ?

 

I ll be glad if anyone can help.

Thanx in advance.

Link to comment
Share on other sites

page.php?id=x

The value of x is probably used to lookup the row containing the content for the page from a database table

photos.php is a completely different file and must have code to get images from a different database table

 

"www.mywebsite.com/page.php?id=photos"

Will not work

 

To save the php code into a mysql field will require php knowledge and modification of the code in page.php to tell it to expect code when id=photos

 

 

Link to comment
Share on other sites

Yes ,but it is not a good idea, here is one way to do it

 

index.php?page=photos

<?php
if(isset($_GET['page']))
{
$page = $_GET['page'];
require_once '$page.php';
}
?>

Not very secure, but it will start you off, or if you want to do it your way

 

You will have a table called content

 

then two rows, one called title and one called content (which will be text, not varchar)

 

Then do

<?php
if(isset($_GET['page']))
{
$page = $_GET['page'];
$page = mysql_real_escape_string($page);
//assuming you are connected to the database
$sql = "SELECT*FROM content WHERE title='$page'";
$query = mysql_query($sql);
while($rows = mysql_fetch_assoc($query))
{
echo $rows['content'];
}
}
?>

 

That should start you off.

Link to comment
Share on other sites

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.