in array twice HELP

[redarrow]

how do u check to see if somethink in a array twice please....

 

my example dosent work so how........

 

if there two names the same in a array i wont it...

 

<?php

$a=array("john","paul","john");

$name="john";

for($i=1; $i<3; $i++){

if(in_array($name,$a)){

echo " in array";

}else{

echo "not in array";
}
}
?>

[DarkWater]

EDIT: Misunderstood.  Here:

 

<?php
$arr = array('john', 'paul', 'john');
$count = array_count_values($arr);
$name = 'john';
if ($count[$name] > 1) {
        echo "$name is a dup!";
}
else {
       echo "$name is NOT a dup!";
}

[redarrow]

my current array looks like this...........

 

Array
(
    [0] => 73.99.134.50

)
Array
(
    [0] => 37.939.163.50

)
Array
(
    [0] => 
)

 

my code

 

 

<?php

$filename = "downloads.log" ;

$dataFile = fopen( $filename, "r" ) ;

if ( $dataFile ){

while (!feof($dataFile)){

$buffer = fgets($dataFile, 4096);
       
$pattern="/([0-9\.]{0,4}[0-9\.]{0,4}[0-9\.]{0,4}[0-9]{0,4})/i";

preg_match_all($pattern,$buffer,$result[]);

$x=implode(' ',$result[0][0]);

$y=explode(' ',$buffer);

print_r($y);

$users_ip=$_SERVER['REMOTE_ADDR'];

$count = array_count_values($y);

if ($count[$users_ip] == 2) {

echo "<center>SORRY OUR RECORDS SHOW US THAT YOU HAVE ALREADY <br> 
DOWNLOADED YOUR FILE PLEASE CONTACT US!<center>";	

EXIT;
}
}

fclose($dataFile);

}else{

die( "fopen failed for $filename" ) ;
  }
?>

 

it wont find the two matches becouse how the array comes out any other idears mate.......

i can not use buffer[0][0]

 

currently the $x implode shows the correct results, but when i use explode you see from the array my results......

[Stooney]

Another way to determine if there's a duplicate in an array

 

<?php
$array=array('a', 'b', 'c', 'a');
foreach($array as $var){
    if(count(array_keys($array, $var))>1){
        echo $var.' is in the array more than once<br>';
    } else{
        echo $var.' is a unique value in the array<br>';
    }
}
?>

[wildteen88]

my current array looks like this...........

 

Array
(
    [0] => 73.99.134.50

)
Array
(
    [0] => 37.939.163.50

)
Array
(
    [0] => 
)

 

my code

 

 

<?php

$filename = "downloads.log" ;

$dataFile = fopen( $filename, "r" ) ;

if ( $dataFile ){

while (!feof($dataFile)){

$buffer = fgets($dataFile, 4096);
       
$pattern="/([0-9\.]{0,4}[0-9\.]{0,4}[0-9\.]{0,4}[0-9]{0,4})/i";

preg_match_all($pattern,$buffer,$result[]);

$x=implode(' ',$result[0][0]);

$y=explode(' ',$buffer);

print_r($y);

$users_ip=$_SERVER['REMOTE_ADDR'];

$count = array_count_values($y);

if ($count[$users_ip] == 2) {

echo "<center>SORRY OUR RECORDS SHOW US THAT YOU HAVE ALREADY <br> 
DOWNLOADED YOUR FILE PLEASE CONTACT US!<center>";	

EXIT;
}
}

fclose($dataFile);

}else{

die( "fopen failed for $filename" ) ;
  }
?>

 

it wont find the two matches becouse how the array comes out any other idears mate.......

i can not use buffer[0][0]

 

currently the $x implode shows the correct results, but when i use explode you see from the array my results......

Are you separating IP addresses by a space within your downloads.log? You'll be better of logging each separate IP on a new line. Then you can just use the following code:

$log_file = 'downloads.log';

// file() returns an array of lines
$ip_log = file($log_file);

// remove new lines
$ip_log = array_map('trim', $ip_log);

// check to see if the users ip is in the $ip_log array
if(in_array($_SERVER['REMOTE_ADDR'], $ip_log))
{
    echo 'Downloaded';
}
else
{
    echo 'Not downloaded';
}