jesushax Posted October 13, 2008 Share Posted October 13, 2008 hi all below is code which gave me a syntax error but i cant see where the error is i got Parse error: syntax error, unexpected T_IF in C:\admin\vacancies\edit_vacancy.php on line 50 which is somewhere in the below snippet can anyone help me out? Cheers $ESQL = mysql_query("SELECT `ID`,`City`,`Cons`,`Ref` FROM `tblVacancies` WHERE `Ref`='$Ref'") or die(mysql_error()); $error = mysql_fetch_array(ESQL); if ($error["Cons"] !="1" || $error["Cons"] !="1") { header("Location: /admin/vacancies/edit_vacancy.php?ID=".$error["ID"]."&action=error1"); } elseif (empty($error["Ref"])) { header("Location: /admin/vacancies/edit_vacancy.php?ID=".$error["ID"]."&action=error2"); } else { header("Location: /admin/vacancies/edit_vac_list.php?CAT=$Cat"); } Link to comment https://forums.phpfreaks.com/topic/128171-solved-syntax-unexpected-if-error-i-cant-see-the-problem/ Share on other sites More sharing options...
JasonLewis Posted October 13, 2008 Share Posted October 13, 2008 Well for one, you're missing the $ in front of ESQL inside mysql_fetch_array(). Other than that, it looks okay too me. Link to comment https://forums.phpfreaks.com/topic/128171-solved-syntax-unexpected-if-error-i-cant-see-the-problem/#findComment-663828 Share on other sites More sharing options...
kenrbnsn Posted October 13, 2008 Share Posted October 13, 2008 You forgot the "$" on the variable $ESQL in this line: <?php $error = mysql_fetch_array(ESQL); ?> Ken Link to comment https://forums.phpfreaks.com/topic/128171-solved-syntax-unexpected-if-error-i-cant-see-the-problem/#findComment-663831 Share on other sites More sharing options...
jesushax Posted October 13, 2008 Author Share Posted October 13, 2008 dammit now i see! thanks Link to comment https://forums.phpfreaks.com/topic/128171-solved-syntax-unexpected-if-error-i-cant-see-the-problem/#findComment-663839 Share on other sites More sharing options...
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